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Lelechka [254]
3 years ago
11

Find the solution set of 1/3x-4≤ 2+x​

Mathematics
2 answers:
Levart [38]3 years ago
5 0

1/3x*3-4*3≤ 2*3+x*3

x-12≤6+3x

-12-6≤3x-x

-18/2≤2x/2

-9≤x

OR

1÷3x-4≤ 2+x

x-12≤6+3x

-12-6≤3x-x

-18/2≤2x/2

-9≤x

Vinil7 [7]3 years ago
4 0

Answer:

[-9 ≤ x] or [x ≥ -9]

Step-by-step explanation:

<u>QUESTION :-</u>

Find the solution set of →  \frac{1}{3} x - 4 \leq  2+ x

<u>SOLUTION :-</u>

  • Simplify the L.H.S.

=> \frac{x-12}{3} \leq x + 2

  • Multiply both the sides by 3

=> \frac{x - 12}{3} \times 3 \leq 3(x + 2)

=> x - 12 \leq  3x +6

  • Substract 'x' from both the sides

=> x - 12 - x \leq 3x + 6 -x

=> -12 \leq 2x + 6

  • Substract 6 from both the sides.

=> -12 - 6 \leq 2x + 6 - 6

=> -18 \leq  2x

  • Divide both the sides by 2.

=> \frac{-18}{2} \leq \frac{2x}{2}

=> -9 \leq x  or  x \geq -9

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