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3 years ago

Solve 2x+3y=6 for y Answers listed: y=-2/3x+2 y=2/3x-2 y=2x-3 y=2x+6

Mathematics

2 answers:

qaws [65]3 years ago

6 0

I think It’s 2/3 x -2

iren2701 [21]3 years ago

4 0

2x + 3y = 6 <=>

3y = -2x + 6 <=>

y = -2/3x + 6/3 <=>

y = -2/3x + 2

The answer is the first one.

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To the nearest tenth the value of x that satisfies 2x = −2x + 11 is

Anuta_ua [19.1K]

To solve for variable equations or inequalities, we want to do two things:
1. Reduce one side to variables only
2. Reduce that side to the variable without coefficients.

The given equation is $2x=-2x+11$ .

Let's perform step 1: reducing one side to variables only. By adding $2x$ to both sides of the equation, we get $4x=11$ .

Now let's perform step 2: reducing that side to the variable without coefficients. Since the coefficient of $4x$ is $4$ , we need to divide both sides of the equation by 4: $x=\frac{11}{4}=2.75$ . Rounded to the nearest tenth, $x=2.8$ .

So the value of $x$ that satisfies $2x=-2x+11$ is $x=2.8$ .

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3 years ago

12 teams are competing in the final round of the world cup soccer conpetition. In how many different ways can the soccer teams f

alex41 [277]

Answer:

I don't know if this is correct, but I'm pretty sure that there are 12 different possible outcomes.

Step-by-step explanation:

The team could either be in 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, or 12th place. This makes 12 outcomes.

7 0

3 years ago

Read 2 more answers

Please help thank you

Dvinal [7]

the tale-tell fellow is the number inside the parentheses.

if that number, the so-called "growth or decay factor", is less than 1, then is Decay, if it's more than 1, is Growth.

$\bf f(x)=0.001(1.77)^x\qquad \leftarrow \qquad \textit{1.77 is greater than 1, Growth} \\\\[-0.35em] ~\dotfill\\\\ f(x)=2(1.5)^{\frac{x}{2}}\qquad \leftarrow \qquad \textit{1.5 is greater than 1, Growth} \\\\[-0.35em] ~\dotfill\\\\ f(x)=5(0.5)^{-x}\implies f(x)=5\left( \cfrac{05}{10} \right)^{-x}\implies f(x)=5\left( \cfrac{1}{2} \right)^{-x} \\\\\\ f(x)=5\left( \cfrac{2}{1} \right)^{x}\implies f(x)=5(2)^x\qquad \leftarrow \qquad \textit{Growth} \\\\[-0.35em] ~\dotfill$

$\bf f(t)=5e^{-t}\implies f(t)=5\left( \cfrac{e}{1} \right)^{-t}\implies f(t)=5\left( \cfrac{1}{e} \right)^t \\\\\\ \cfrac{1}{e}\qquad \leftarrow \qquad \textit{that's a fraction less than 1, Decay}$

now, let's take a peek at the second set.

$\bf f(x)=3(1.7)^{x-2}\qquad \leftarrow \qquad \begin{array}{llll} \textit{the x-2 is simply a horizontal shift}\\\\ \textit{1.7 is more than 1, Growth} \end{array} \\\\[-0.35em] ~\dotfill\\\\ f(x)=3(1.7)^{-2x}\implies f(x)=3\left(\cfrac{17}{10}\right)^{-2x}\implies f(x)=3\left(\cfrac{10}{17}\right)^{2x} \\\\\\ \textit{that fraction is less than 1, Decay} \\\\[-0.35em] ~\dotfill$

$\bf f(x)=3^5\left( \cfrac{1}{3} \right)^x\qquad \leftarrow \qquad \textit{that fraction is less than 1, Decay} \\\\[-0.35em] ~\dotfill\\\\ f(x)=3^5(2)^{-x}\implies f(x)=3^5\left( \cfrac{2}{1} \right)^{-x}\implies f(x)=3^5\left( \cfrac{1}{2} \right)^x \\\\\\ \textit{that fraction in the parentheses is less than 1, Decay}$

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3 years ago

The profits for the week was $1200. the amount spend was $975 . find the revenue for the week

Kryger [21]

You get $1200-$975=225

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3 years ago

A class voted for either rollerblading, swimming, or biking as their favorite summer activity. If swimming got 42% percent of th

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3 years ago