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Vitek1552 [10]
3 years ago
11

Solve 2x+3y=6 for y Answers listed: y=-2/3x+2 y=2/3x-2 y=2x-3 y=2x+6

Mathematics
2 answers:
qaws [65]3 years ago
6 0
I think It’s 2/3 x -2
iren2701 [21]3 years ago
4 0
2x + 3y = 6 <=>

3y = -2x + 6 <=>

y = -2/3x + 6/3 <=>

y = -2/3x + 2

The answer is the first one.
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Jake went to a fair and spent $5 on admissions, $6.50 on games, and $7.21
asambeis [7]

Answer:

Jake has <em>$11.29 </em>dollars left.

Step-by-step explanation:

To find the answer, we will add up<em> $5 + $6.50 + $7.21</em> and we get<em> $18.71</em>.  Now <em>subtract $30 from 18.71</em>, which is <em>$11.29</em>.  Therefore, <em>Jake has $11.29 dollars left.</em>

8 0
3 years ago
Need to find the direction angle for each vector. #10 and #12 please!
crimeas [40]

Answer:

10)  - 45 degrees

12)  0 degrees

Step-by-step explanation:

10)

Find the x and y components that define the vector that joins C with D:

x-component: -4 - (-8) = - 4 + 8 = 4

y-component:  4 - 8 = -4

use the tangent function to find the angle \theta:

tan(\theta)=\frac{y-comp}{x-comp}=\frac{-4}{4}  = -1\\\theta = -45^o

12)

Find the x and y components that define the vector that joins A with B:

x-component: 7 - 4 = 3

y-component:  - 1 - (-1) = -1 + 1 = 0

use the tangent function to find the angle \theta:

tan(\theta)=\frac{y-comp}{x-comp}=\frac{0}{3}  = 0\\\theta = 0^o

5 0
3 years ago
Help please!! Quick
Finger [1]

Step-by-step explanation:

Solve for a:

Step 1: Multiply both sides by b.

b=a

Step 2: Flip the equation.

a=b

---------------------------

Solve for b:

Step 1: Multiply both sides by b.

b=a

4 0
3 years ago
How do you solve thsi
VLD [36.1K]
You multiply the length of the model car by the meters from the actual car. It’s easier to convert one unit of measurement to match with the other. I found it easier to convert 18.2 cm to meters which is 0.182 m. Now we multiply 0.182m by 0.3m to get the length of the actual car.

The answer would be 0.0546m. Or if you prefer centimeters, then the answer would be 5.46 cm. Either way is fine.

Hope this helped, please let me know if I was correct. :D
5 0
3 years ago
A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the
EastWind [94]

Answer:

a) \hat p=\frac{471}{1024}=0.460

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Data given and notation  

n=1024 represent the random sample taken    

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

\hat p=\frac{471}{1024}=0.460 estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering    

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

Part b

If we replace the values obtained we got:

0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429

0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491

The 99% confidence interval would be given by (0.429;0.491)

8 0
3 years ago
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