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3 years ago

Solve for y. 6 = 2 (y+2)

Mathematics

2 answers:

storchak [24]3 years ago

8 0

Answer:

y= 1

Step-by-step explanation:

6 = 2(y + 2)

6 = 2y + 4 (distribute)

6-4 = 2y + 4-4 (inverse operation)

2/2 = 2y/2 (simplify)

1 = y or y = 1

Ad libitum [116K]3 years ago

4 0

Start by dividing both sides by two to get 3 = y + 2. then subtract two from both sides to get y = 1.

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The 7th grade had a book drive. They donated 2/3 of the books to the st James school. Then donated 1/4 of the remaining books to

sergiy2304 [10]

Answer: 192 books

Step-by-step explanation:

2/3 + 1/4 = 11/12

16 remaining books = 1/12

16 x 11 = 176

176 + 16=192

7 0

3 years ago

Read 2 more answers

(3×10 – 4)(2×1010) whats the scientific notion

Rudik [331]

The result of the multiplication in scientific notation is given by:

$6 \times 10^{6}$

<h3>What is scientific notation?</h3>

A number in scientific notation is given by:

$a \times 10^b$

With the base being $a \in [1, 10)$ .

When we multiply two numbers in scientific notation, we multiply the bases and add the exponents.

For this problem, the numbers are given by:

$3 \times 10^{-4}, 2 \times 10^{10}$

The result of the multiplication is given by:

$3 \times 10^{-4} \times 2 \times 10^{10} = 6 \times 10^{-4 + 10} = 6 \times 10^{6}$

The result of the multiplication in scientific notation is given by:

$6 \times 10^{6}$

More can be learned about scientific notation at brainly.com/question/16394306

#SPJ1

6 0

1 year ago

REPOST!!!!!! 20 POINTS!!!!!!

kkurt [141]

Answer:

Step-by-step explanation:

according to tangent property

we get

AM=BM
AN=CN
BK=CK

Given that

AM=6
BK=4

Thus our equation is

$\rm \displaystyle 2AM + 2AN + 2BK = 34$

substitute the given values

$\rm \displaystyle 2.6+ 2AN+ 2.4 = 34$

simplify multiplication:

$\rm \displaystyle 12+ 2AN+ 8 = 34$

simplify addition:

$\rm \displaystyle 2AN+ 20= 34$

cancel 20 from both sides:

$\rm \displaystyle 2AN=14$

divide both sides by 2:

$\rm \displaystyle AN=7$

AN=CN

hence,CN=7

therefore our answer is A

6 0

3 years ago

I need help on this one please

zepelin [54]

Answer:

here is what i think

3 0

3 years ago

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago