All categories

3 years ago

What is the constant term in the expansion of the binomial (2x + 3)3?

Mathematics

1 answer:

guajiro [1.7K]3 years ago

4 0

The answer is 27 but I am not sure I hope my calculations ain't wrong

You might be interested in

At the Tucson Zoo, Jason spends $6.00 to enter the zoo and $2.00 per animal to feed them. Meanwhile, at the Phoenix Zoo, Kim spe

shtirl [24]

Answer:

3 animals

Step-by-step explanation:

combine like terms

6 + 2x = 15 + x
-6 + x - 6 - x

--------------------------

3x = 9

2. divide both sides by 3

3x/ 3 = 9/3
x = 3

8 0

3 years ago

Admission to a car show costs $5 for each ticket. After selling only 20 tickets, they decided to lower the price to $3 each. If

Naddik [55]

First you would multiple 5 × 20 which equals $100 then you would subtract $217 by $100 and you would get 39 tickets and then you would add your twenties tickets and your 39 tickets together to get your answer which is 59 tickets.

5 0

3 years ago

Read 2 more answers

Curtis decided to go on a road trip to Canada. On the first day of his trip, he drove for 15 hours and traveled 1,005 miles. At

Radda [10]

Answer:

Step-by-step explanation:

1,005 / 15 = 67

3 0

3 years ago

Read 2 more answers

what is the equation subtracting 7 from the product of 4 and a number results in the number added to 29

vitfil [10]

That would be:-

4x - 7 = x + 29

the solution:-

3x = 29 + 7

3x = 36

x = 12

7 0

3 years ago

Hello.

melisa1 [442]

Answer:

$\large{\boxed{\sf 2y^2\sqrt{2y}}}$

Step-by-step explanation:

Here the given expression to us is ;

$\sf\qquad\longrightarrow \dfrac{\sqrt{64xy^5}}{\sqrt{8x}}$

Recall that ,

$\sf\qquad\longrightarrow \dfrac{\sqrt{x}}{\sqrt{y}}=\sqrt{\dfrac{x}{y}}$

On using this , we have ;

$\sf\qquad\longrightarrow \sqrt{\dfrac{\cancel{64}\cancel{x}y^5}{\cancel{8x}}}$

Simplify ,

$\sf\qquad\longrightarrow \sqrt{ 8 y^5}$

The prime factorisation of 8 is 2³ . So ;

$\sf\qquad\longrightarrow \sqrt{ (2^3)(y^5)} =\sqrt{(2^2)(2)(y^2)(y^2)(y)}$

Simplify the square root ,

$\sf\qquad\longrightarrow \pink{ 2y^2\sqrt{2y}}$

Hence the required answer is 2y²√{2y} .

6 0

2 years ago

Read 2 more answers