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Solution:- In the given figure
Side of square= 10 cm
area of square = side x side m= 10 x 10 = 100 sq cm
Now , diameter of semi circle AOD = 2r = 10cm
⇒ radius of semi circle AOD = 5 cm
∴ area of AOD =
similarly Area of semicircle BOC =
Area of white portion in figure 1 = area of square - [ area of semicircle BOD + area of semicircle AOD]
=
Total area of white portion in the given figure=
∴Area of Shaded portion = area of square - area of total white portion
=
So the area of shaded portion is
Now perimeter of AD(which is a semicircle) = (as perimeter of semicircle=πr)
So the perimeter of shaded region = 4×perimeter of AD=4×15.7=62.8cm
