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2 years ago

~!!!! HELPPPPPPPPP IM IN 7Th GRADE LEARNING 9TH AND 8TH HELP PLEASE !!!!~

Mathematics

1 answer:

Dafna1 [17]2 years ago

5 0

Answer:

Step-by-step explanation:

Plug the point (-1,20) into the equation.

20 = a|-1|+7

13 = a|-1|

13 = a ⋅ 1

a= 13

:::::

(1,20) is another point on the graph.

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You spin the spinner shown below once. Each sector shown has an equal area.

a_sh-v [17]

Answer: P(not shaded sector) = 0.50

Step-by-step explanation:

Since we have given that

Number of shaded parts = 6

Number of unshaded parts = 6

Total parts = 6+6 = 12

So, Probability of getting not shaded sector is given by

$\dfrac{6}{12}\\\\=\dfrac{1}{2}\\\\=0.50$

Hence, P(not shaded sector) = 0.50

8 0

3 years ago

Two cards are drawn at random without replacement from a deck of 52 playing cards. If the first card chosen is a King, what is t

gulaghasi [49]

Answer:

p=0.05882

Step-by-step explanation:

Probability is the likelihood of an event occurring.

-A standard deck of cards has 4 kings.

#After one card is removed, 51 remains of which 3 are kings:

$P(king)=\frac{3}{51}\\\\=0.05882$

Hence, the probability that the second card is king is 0.05882

3 0

2 years ago

Read 2 more answers

How do you graph? <br> y=−4/3x+8y

trasher [3.6K]

How do we graph anything? Make a table of values for x and y and then plot each point. After plotting each point on the xy-plane, connect each point with a straight line or curve (depending on the function).

In this case, we must first isolate y.

y = (-4/3)x + 8y

y - 8y = (-4/3)x

-7y = (-4/3)x

y = (-4/3)x ÷ (-7)

y = (4/21)x

Now follow the steps above.

8 0

2 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

3 years ago

Answer and explanation plz ???

Nutka1998 [239]

Answer:

Step-by-step explanation:

Formula

2xy + 1

Givens

x = 3

y = 4

Solve

2*(3)*(4) + 1

24 + 1

7 0

3 years ago