Answer:
4 5/12
Step-by-step explanation:
Rewriting our equation with parts separated
Solving the whole number parts
Solving the fraction parts
Find the LCD of 1/4 and 5/6 and rewrite to solve with the equivalent fractions.
LCD = 12
Combining the whole and fraction parts
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
476.00×5%=23.80 tax=476+23.80=499.80
499.80×15%=74.97
499.80+74.97=574.77
TU=AB since they are congruent figure. So AB=13
Answer:
256
Step-by-step explanation:
64*4
(60*4)+(4*4)
240+16
256
you could also take a different approach--
64=4^3
4^3*4=4^4
4^4=16^2=256
