The results will always equal a positive
<span>x^2y=xy^2
Differentiate implicitly.
x^2y' + y(2x) = x(2yy') + y^2
x^2y' + 2xy = 2xyy' + y^2
x^2y' - 2xyy' = y^2 - 2xy
y'(x^2 - 2xy) = y^2 - 2xy
y' = (y^2 - 2xy)/(x^2 - 2xy)</span><span />
Burrito: 20
hot sauce: 80
taco: 400
