Answer:
xopoorxo
Step-by-step explanation:
12
Answer:
Probability of a train on line A arriving on time: 80%
Probability of any train arriving on time: 96%
Step-by-step explanation:
If 18 of the 90 incoming trains on line A arrive late, we have that 90 - 18 = 72 trains of the 90 arrive on time, so the probability of a train on line A arriving on time is:
P(A) = 72/90 = 0.8 = 80%
on line B, we have that 70 - 14 = 56 trains of the 70 arrived in time, so the probability of a train from line B arriving on time is:
P(B) = 56/70 = 0.8 = 80%
To find the probability of any train arriving on time, we can use this formula:
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.8 + 0.8 - 0.8*0.8
P(A or B) = 1.6 - 0.64 = 0.96 = 96%
Given:
CDEF is dilated by a scale factor of 
to form the quadrilateral C'D'E'F'.
To find:
The measure of side E'F'.
Solution:
If a figure is dilated by a scale factor of k, then the side of dilated figure is k times of corresponding side of original figure.
CDEF is dilated by a scale factor of to form the quadrilateral C'D'E'F'. So,
From the given figure it is clear that 
. So,
Therefore, the measure of side E'F' is 9 units.
If the line is reading right its -2 if its reading left its -10
Answer: 6.7
Have a good day :D
