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scoundrel [369]
3 years ago
12

Help plz it easy math for people above 6th grade​

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0
Your coefficient is the number and your variable is the letter. So in this case your coefficients are 9 and 20 and your variables are x and y!
Lana71 [14]3 years ago
6 0
Coefficients are 9 and 20
variables are x and y
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Given that y varies jointly as x and z, and y = 13 when x = 5
seraphim [82]

Step-by-step explanation:

y=kxz

13=k x 5 x 8

13= 40k

K=13/40

a. y=13/40 x 4 x 10

y=13/40 x 40

y=13

b. 20=13/40 x x x 12

20=13/40 x 12x

20=<u>156x</u>

40

20 x 40=156x

800=156x

X=<u>800</u>

156

X=<u>200</u>

39

X=5 5/39

C. 15=13/40 x 6 x z

15=<u>78z</u>

40

15x40=78z

600=78z

Z=<u>600</u>

78

Z=<u>100</u>

3

Z=7 9/13

6 0
3 years ago
The length of a rectangle is 5 units more than twice its width. Find an expression for the perimeter of the rectangle.
kolezko [41]
The width would be 10
length would be 15
8 0
3 years ago
Evaluate the series 4 sigma n=1 n+4
musickatia [10]

Answer:

\sum _{n=1}^4n+4=26

Step-by-step explanation:

 Given : \sum _{n=1}^4\:n+4

We have to evaluate the sum.

 

Consider , the given sum \sum _{n=1}^4\:n+4

Apply the sum rule, \sum a_n+b_n=\sum a_n+\sum b_n    

we have,

=\sum _{n=1}^4n+\sum _{n=1}^44

Consider \sum _{n=1}^4n first,

Applying sum formula, \sum _{k=1}^nk=\frac{1}{2}n\left(n+1\right)

Here, n = 4, we get,

=\frac{1}{2}\cdot \:4\left(4+1\right)

\sum _{n=1}^4n=10

Now consider \sum _{n=1}^44

\mathrm{Apply\:the\:Sum\:Formula:\quad }\sum _{k=1}^n\:a\:=\:a\cdot n

=4\cdot \:4=16

Therefore, =\sum _{n=1}^4n+\sum _{n=1}^44=10+16=26

Thus, \sum _{n=1}^4n+4=26

6 0
4 years ago
Read 2 more answers
The box plots show the student grades on a chapter test compared to the grades on a retest in the same class. Box plots titled C
a_sh-v [17]

Answer:

Step-by-step explanation:

C

8 0
3 years ago
1. What is the general form of the equation for this line y-5= -3(x + 4)?
ivanzaharov [21]

Answer:

I think its B

8 0
2 years ago
Read 2 more answers
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