Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
Answer:
$-275.12
Step-by-step explanation:
because 420.35+ -275.12=145.23
Honestly I can’t remember the last time I had to deal with arcs in school, but the answer to the second one is 63 because all triangles add up to 180 degrees and 46+71= 117. 180-117=63
This is the solution of the equation, where a=1, b=-5, c=7
So the discriminant is :
b^2-4ac=25-4*7= -3
The square root of -3 is non-real, this both solutions are non-real.
