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sleet_krkn [62]
3 years ago
5

X * 2/3 < 2/3 Solve for x

Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0

Answer:

x<1

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable. Hope this helps!

liubo4ka [24]3 years ago
4 0

Answer:x<1

Step-by-step explanation:

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Find the equation of the linear function represented by the table below in slope-
Anarel [89]

Answer:

y = 3x + 5

Step-by-step explanation:

slope:

11 - (-1) / 2 - (-2) = 12/4 = 3

slope intercept form is y = mx + b, so right now you have m = 3:

y = 3x + b

now, since you know x = -2 and y =-1 is a solution, you can plug those values in:

-1 = 3 * -2 + b

-1 = -6 + b

5 = b

This means the equation is y = 3x + 5

5 0
3 years ago
Read 2 more answers
Qbjsksnnfkkdnnwnnsiodnnjfkjbbskkxkkdn
iris [78.8K]

Answer:

There are 25 students in the class.

Step-by-step explanation:

Since we know the percentage of students who want an ice cream party is 20%, and 5 students want an ice cream party, we know that:

\frac{5}{S}=0.2

, where S is the total amount of students. We can then solve for S:

\frac{5}{S}=0.2 Given equation

5=0.2*S Multiply by S

25=S Divide by 0.2

Therefore, there are 25 students in the class.

7 0
3 years ago
Read 2 more answers
Two less than 2 times a number is the same as the number plus 64
Schach [20]
In math for we have:
2x-2=x+64
which turns into:
x=66

(subtract x from right) & (add two from left)
8 0
3 years ago
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A college survey was taken to determine where students study. Of 110 students surveyed, 64 studied
Serhud [2]

Answer:

12

Step-by-step explanation:

64+52=118 studied in the cafeteria or lounge

but 20 studied in both, so 118-20 = 98 studied there in total

110 -98 = 12

8 0
3 years ago
Let y(????)y(t) be a solution of y˙=17y(1−y7)y˙=17y(1−y7) such that y(0)=14y(0)=14. Determine lim????→[infinity]y(????)limt→[inf
shtirl [24]

Answer:

Step-by-step explanation:

Given that,

y' = 17y ( 1-y^7)

Let y=1

Then, y' = 0 for all t

Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.

So, the graph solution will be

y(0) = 1 and this will be an horizontal line

If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.

Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.

So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.

This make the limit be 1.

This shows that x = 1 is a stable equilibrium.

6 0
3 years ago
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