Answer:
4989600 ways
Step-by-step explanation:
From the question,
The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)
⇒ n!/(r₁!r₂!r₃!) ways
Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.
Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2
Substitute these value into the expression above
11!/(2!2!2!) = (39916800/8) ways
4989600 ways
Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways
Answer:
<h3>5^3</h3>
Step-by-step explanation:
There should be a regular 5 with a little three to the top right corner of the 5.
Answer:
5-9i
Step-by-step explanation:
If you add the 4 and 1 you get 5, and if you add -7i and -2i since they are both negative, they stay negative, so you get -9i. So the answer is 5-9i.
