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solong [7]
3 years ago
15

What is the median number of points scored by the two players. WILL GIVE BRAINLY.

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:

10.5

Step-by-step explanation:

6, 7,8, 9,10, 11, 12, 15, 16, 17

10+11= 21

21÷2= 10.5

When there is an even number of values in a set of data, there is no single middle value. That makes it a little more difficult to find the median. In his case, you take the two middle values and add them together. Then you divide the sum by of the values by 2. This gives you the median.

velikii [3]3 years ago
5 0

Answer:

11

Step-by-step explanation:

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The weight of Jacob’s backpack is made up of the weight of the contents of the backpack as well as the weight of the backpack
ryzh [129]

The equation can be used to determine t, the weight of the textbooks is t = 0.7w

Given:

let

Total weight = w

Weight of notebook = n

Weight of backpack = b

Weight of textbook = t

w = n + b + t

where

n = 4 pounds

b = 2 pounds

t = 0.7w

So

w = 4 + 2 + 0.7w

w - 0.7w = 4 + 2

0.3w = 6

w = 6/0.3

w = 20

Recall,

t = 0.7w

= 0.7(20)

= 14 pounds

Therefore, the weight of the textbook is 14 pounds

Learn more about equation:

brainly.com/question/4916384

5 0
3 years ago
Eugene spent $14 on a magazine and some candy bars. if theagazine cost $6 and each candy bar cost $2 then hpw many candy bar did
Inessa05 [86]
14=6+2x
subtract 6 from both sides
8=2x
divide both sides by 2
x=4 candy bars

5 0
3 years ago
Can someone answer this
shepuryov [24]
Your answer for 15 is D or C. For 16 I’m estimating 125?
3 0
2 years ago
Evaluate each expression please
Firlakuza [10]
13. Is 18 15. Is 86 17 is 5 19 is 15 21 is 24 23 is 29
5 0
3 years ago
If f(x)=5x^3 and g(x)=x+1, find (f•g)(x)
alukav5142 [94]

Hello from MrBillDoesMath!

Answer:

5 x^3 + 15 x^2 + 15 x + 5 , none of the provided choices

Discussion:

f(x) = 5 x^3

g(x) = x+ 1  

=>

(f•g)(x) =

f(g(x)) =

f(x+1) =

5 * (x+1)^3 =

5 x^3 + 15 x^2 + 15 x + 5

which is none of the provided answers.

Thank you,

MrB

5 0
3 years ago
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