Answer:
more than 200 calls
Suppose number of calls = x
According to plan 1: Total monthly charge is $24
According to plan 2: Fix charge is $16 and $0.04 per call
cost of x's call = $0.04x
and monthly charge according to plan 2 = 0.04x + 16
a) Plan 1 is more economical than plan 2.
0.04x + 16 > 24
solve it for x
.04x > 8
x > 200
b) So, if more than 200 calls are made then Plan 1 is more economical.
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Because in graph there are boxes
And boxez are squre
And C is the answer
You Fool
Yoo Fool
The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
Answer:
6
Step-by-step explanation:
$603 dollars ÷ 100 shoppers = $6.03 per shopper, or 6
as a mixed number
Answer:
a = 6
Step-by-step explanation:
Hello!
Solve:
- 4(3a - 4) = 56
- 3a - 4 = 14 (factoring out 4)
- 3a = 18 (adding 4 to both sides)
- a = 6 (dividing by 3)
Another way:
- 4(3a - 4) = 56
- 12a - 16 = 56 (distributive property)
- 12a = 72 (moving like terms)
- a = 6 (dividing by 12)
Distributive Property of Multiplication:
The process of distributing the outside factor to the terms in the parenthesis.
Example:
