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GarryVolchara [31]
3 years ago
14

PLEASE HELP! I WILL MARK BRAINLIEST!

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Answer:

D) There are no outliers.

Step-by-step explanation:

First step is to put the values in order:

15, 20, 25, 30, 35, 40, 45, 45, 50, 55, 60

Then, find the median. 40 is the median because it is in the middle.

A point is considered an outlier if it is greater than 1.5 interquartile ranges below the first quartile or above the third quartile.

To find the first quartile, take the median of all values to the left of 40. The median of 15, 20, 25, 30, 35 is 25 because it is in the middle. So the first quartile is 25.

The third quartile is 50 because it is the middle of the values to the right of 40.

Then, multiply the interquartile range by 1.5

The interquartile range is 25 because the 3rd quartile (50) minus the 1st quartile (25) is 25. Multiply 25 by 1.5 and you get 37.5.

An outlier is anything less than Q1 - 37.5 and anything more than Q3 + 37.5.

Q1 is 25. 25 - 37.5 is -12.5

Q3 is 50. 50 - 37.5 is 12.5

None of the values are outliers because they aren't 12.5 less than Q1 or 12.5 more than Q3.

Sphinxa [80]3 years ago
3 0
Answer D.) There are no outliers, sorry if i’m wrong.
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The required linear equation satisfying the given conditions f(-1)=4 and f(5)=1 is $y=\frac{-1}{2} x+\frac{7}{2}$

Step-by-step explanation:

It is given that f(-1)=4 and f(5)=1.

It is required to find out a linear equation satisfying the conditions f(-1)=4

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$$\left(y-y_{2}\right)=m\left(x-x_{2}\right)$$

Step 1 of 4

Observe, f(-1)=4 gives the point (-1,4)

And f(5)=1 gives the point (5,1).

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Step 2 of 4

Now find out the slope of a line passing through the points (-1,4) and (5,1),

$$\begin{aligned}&m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\&m=\frac{1-4}{5-(-1)} \\&m=\frac{-3}{5+1} \\&m=\frac{-3}{6} \\&m=\frac{-1}{2}\end{aligned}$$

Step 3 of 4

Now use the slope $m=\frac{-1}{2}$ and use one of the two given points and write the equation in point-slope form:

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Distribute $\frac{-1}{2}$,

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Step 4 of 4

This linear function can be written in the slope-intercept form by adding 1 on both sides,

$$\begin{aligned}&y-1+1=\frac{-1}{2} x+\frac{5}{2}+1 \\&y=\frac{-1}{2} x+\frac{5}{2}+\frac{2}{2} \\&y=\frac{-1}{2} x+\frac{7}{2}\end{aligned}$$

So, this is the required linear equation.

8 0
2 years ago
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