All categories

3 years ago

PLEASE HELP! I WILL MARK BRAINLIEST!

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

8 0

Answer:

D) There are no outliers.

Step-by-step explanation:

First step is to put the values in order:

15, 20, 25, 30, 35, 40, 45, 45, 50, 55, 60

Then, find the median. 40 is the median because it is in the middle.

A point is considered an outlier if it is greater than 1.5 interquartile ranges below the first quartile or above the third quartile.

To find the first quartile, take the median of all values to the left of 40. The median of 15, 20, 25, 30, 35 is 25 because it is in the middle. So the first quartile is 25.

The third quartile is 50 because it is the middle of the values to the right of 40.

Then, multiply the interquartile range by 1.5

The interquartile range is 25 because the 3rd quartile (50) minus the 1st quartile (25) is 25. Multiply 25 by 1.5 and you get 37.5.

An outlier is anything less than Q1 - 37.5 and anything more than Q3 + 37.5.

Q1 is 25. 25 - 37.5 is -12.5

Q3 is 50. 50 - 37.5 is 12.5

None of the values are outliers because they aren't 12.5 less than Q1 or 12.5 more than Q3.

Sphinxa [80]3 years ago

3 0

Answer D.) There are no outliers, sorry if i’m wrong.

You might be interested in

What is 540 divided by 100?

Vanyuwa [196]

I hope this helps you

540/100

54/10

5,4

5 0

2 years ago

Which expression does the model represent?

Fed [463]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

<u>Step-by-step explanation:</u>

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$