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Georgia [21]
3 years ago
10

a car dealer needs to move 260 cars and a transport truck can hold 8 cars 1a: How many trucks will the car dealer need to transp

ort the cars? 1b: how many of the trucks will be full? 1c: how many cars will be on the final transport truck?
Mathematics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

1a) the car dealer will need 33 trucks to transport the cars

1b) 32 trucks will be full

1c) there will be 4 cars in the final truck

Step-by-step explanation:

- cars = 260

- 1 truck = 8 cars

= 260 ÷ 8 = 32.5 (rounded to 32)

= 32 × 8 = 256

= 260 - 256 = 4

- trucks needed = 33

- final truck = 4 cars

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gulaghasi [49]

Answer:

(x-10)²+(y+9)²= 324.

Step-by-step explanation:

For this question, you will need to substitute these values into the equation of a circle:

(x-h)²+(y-k)²= r²

'h and k' represent the center points, and 'r' represents the radius.

This will result in:

(x-10)²+(y+9)²=324.

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3 years ago
More help please lol
amm1812

Answer:

46.03 = 46.030

Step-by-step explanation:

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3 years ago
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KatRina [158]

Answer:

\frac{15}{2} , \frac{11}{2}

Step-by-step explanation:-

To find the midpoint, the equation we use is:-

\frac{x1 +x2}{2} , \frac{y1 + y2}{2}

x1 = 10

x2 = 5

y1 = 7

y2 = 4

Substituting the values in the equation, we get:-

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3 years ago
If total liabilities decreased by $60,000 and stockholders' equity increased by $20,000 during a period of time, then total asse
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Answer:

$40,000 decrease

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This perimeter = 4x -1 (1 less than 4 times the shortest side).

Then x + x + 1 + x + 2 = 4x - 1
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