Step-by-step explanation:
length = (2x + 3) units
width = (x - 7) units
Area = 2( length × width)
Area = 2( (2x + 3) × (x - 7) )
Area = 2( 2x² - 14x + 3x - 21)
Area = 2 ( 2x² -11x - 21)
Area = 4x² - 22x - 42
Answer:
5 units
Step-by-step explanation:
According to the given statement Δ XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z' which means that each point in ΔXYZ is moved 4 units up and moved 3 units left.
To find the distance of each corresponding point we will use the Pythagorean theorem which states that the square of the length of the Pythagorean of a right triangle is equal to the sum of the squares of the length of other legs
The square of the required distance = 4^2+3^2 = 16+9 =25
By taking root of 25 we get:
√25 = 5
Thus, we can conclude that the the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ is 5 units.
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