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2 years ago

Help I need homework pls help mee

Mathematics

2 answers:

Aleksandr-060686 [28]2 years ago

7 0

Answer:

4a 2/7.

I could solve just this

gayaneshka [121]2 years ago

5 0

Answer:

For #3b, shade in 1 1/2 bars

For 4a, i think it is 3/7

4b is prob 43%

5 i think is abt 0.2 miles

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What is the graph of y = x - 3 (shown below) translated up 2 units?

Mrac [35]

I don't see a "shown below," so I'm not sure if I could accurately answer your question. However, if your graph point is (x,-3), then it wants you to move your graphed point up two units. I believe that would be y = x -1? I'm not sure

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3 years ago

Read 2 more answers

Yall can u please help me this is a grade i really need All answers before<br> 9:30

il63 [147K]

Answer:

Step-by-step explanation:

11: 16

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2 years ago

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can use as an estimator for p $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

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2 years ago

Factor the following<br> polynomial:<br> X^3 + 125

ra1l [238]

X^3 + 5^3
(x+5)x(x^2-X x 5+5^2)

(x+5)x(x^2 -5x+5^2)

(x+5)x(x^2 -5x+25)

(x+5) x (x^2 -5x+25)

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2 years ago

Why might Razis method not be a good way to estimate the probability? My team won 18 of their last 20 matches, so the probabilit

FrozenT [24]

Answer:

It is a really idealistic way to estimate probability.

It usually works well for random events where there is no restriction like:

"There are N elements in a set, the probability of randomly selecting any element is the same (so there is no restriction) meaning that for every single element, the probability is 1/N.

Now suppose that there are K elements (K < N) with a given characteristic, then the probability of randomly selecting one of the K elements out of the sett with N elements is equal to K times the probability of each element, this is:

P = K*(1/N) = K/N"

Then if a dice has 6 possible outputs, and we want to find the probability of getting a 3 or a 5, we need to find the quotient between the outcomes where we get a 3 or a 5 (2) and the total number of outcomes (6)

P = 2/6

Now let's go to the case in the problem:

We know that out of the last 20 games, your team won 18.

Then yes, your team won (18/20)*100% = 90% of their played games.

Does this mean tath the probability of winning the next game is 90%?

Well no, because this is not a random selection, there are a lot of other things needed to analyze, as the win rate of the other team (suppose that the other team won 14 of their last 20 games, then their win rate is (16/20)*100% = 70%

Does this mean that the probability where our team wins is 90%, and the probability of the enemy team winning is 70%?

Well no, this makes no sense at all, and this is why this method is not a good way to estimate probability in complex cases like this one.

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2 years ago

Help I need homework pls help mee​

Help I need homework pls help mee