1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
I am Lyosha [343]
3 years ago
10

Help please, look The picture !

Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

Ha ha what I was doing is just looking at the picture.

OK jokes aside

The correct answer should be

option d (-0.25)

You might be interested in
Find the value of x so that the function has the given value. f(x) = 3 – 2x; f(x) = -5
Brrunno [24]
F(-5)= 3-2(-5)
= 3+10
= 13

Hope it helps :))
4 0
3 years ago
Jerry has an insurance policy with a premium of $150 per month. in june, he's in an accident and receives a bill with a
EastWind [94]

Answer:

he will have to pay $650 in the month of june

3 0
2 years ago
Question 1(Multiple Choice Worth 4 points)
ICE Princess25 [194]

The answer would be A) The product of a constant factor of four and a factor with the sum of two terms.

The expression 4(y + 6) is the product of two factors: 4 and (y + 6).

4 is a constant factor; the value will remain as 4 regardless of the y value.

The second factor, (y + 6), represents a sum of two terms: y and 6.

Therefore, A is the correct answer.

7 0
3 years ago
Read 2 more answers
Please help due today
Galina-37 [17]

Answer:

cubic hahahabqbnqnwnw

4 0
3 years ago
Determine the above sequence converges or diverges. If the sequence converges determine its limit​
marshall27 [118]

Answer:

This series is convergent. The partial sums of this series converge to \displaystyle \frac{2}{3}.

Step-by-step explanation:

The nth partial sum of a series is the sum of its first n\!\! terms. In symbols, if a_n denote the n\!th term of the original series, the \! nth partial sum of this series would be:

\begin{aligned} S_n &= \sum\limits_{k = 1}^{n} a_k \\ &=  a_1 + a_2 + \cdots + a_{k}\end{aligned}.

A series is convergent if the limit of its partial sums, \displaystyle \lim\limits_{n \to \infty} S_{n}, exists (should be a finite number.)

In this question, the nth term of this original series is:

\displaystyle a_{n} = \frac{{(-1)}^{n+1}}{{2}^{n}}.

The first thing to notice is the {(-1)}^{n+1} in the expression for the nth term of this series. Because of this expression, signs of consecutive terms of this series would alternate between positive and negative. This series is considered an alternating series.

One useful property of alternating series is that it would be relatively easy to find out if the series is convergent (in other words, whether \displaystyle \lim\limits_{n \to \infty} S_{n} exists.)

If \lbrace a_n \rbrace is an alternating series (signs of consecutive terms alternate,) it would be convergent (that is: the partial sum limit \displaystyle \lim\limits_{n \to \infty} S_{n} exists) as long as \lim\limits_{n \to \infty} |a_{n}| = 0.

For the alternating series in this question, indeed:

\begin{aligned}\lim\limits_{n \to \infty} |a_n| &= \lim\limits_{n \to \infty} \left|\frac{{(-1)}^{n+1}}{{2}^{n}}\right| = \lim\limits_{n \to \infty} {\left(\frac{1}{2}\right)}^{n} =0\end{aligned}.

Therefore, this series is indeed convergent. However, this conclusion doesn't give the exact value of \displaystyle \lim\limits_{n \to \infty} S_{n}. The exact value of that limit needs to be found in other ways.

Notice that \lbrace a_n \rbrace is a geometric series with the first term is a_0 = (-1) while the common ratio is r = (- 1/ 2). Apply the formula for the sum of geometric series to find an expression for S_n:

\begin{aligned}S_n &= \frac{a_0 \cdot \left(1 - r^{n}\right)}{1 - r} \\ &= \frac{\displaystyle (-1) \cdot \left(1 - {(-1 / 2)}^{n}\right)}{1 - (-1/2)} \\ &= \frac{-1 +  {(-1 / 2)}^{n}}{3/2} = -\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\end{aligned}.

Evaluate the limit \displaystyle \lim\limits_{n \to \infty} S_{n}:

\begin{aligned} \lim\limits_{n \to \infty} S_{n} &= \lim\limits_{n \to \infty} \left(-\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\right) \\ &= -\frac{2}{3} + \frac{2}{3} \cdot \underbrace{\lim\limits_{n \to \infty} \left[{\left(-\frac{1}{2}\right)}^{n} \right] }_{0}= -\frac{2}{3}\end{aligned}}_.

Therefore, the partial sum of this series converges to \displaystyle \left(- \frac{2}{3}\right).

8 0
3 years ago
Other questions:
  • the mendez family just bought a home for 180,000 if the value of the home increases at a rate of 3% per year, use an exponential
    8·1 answer
  • Find values of a and b that make the following equality into identity:
    12·1 answer
  • How many different ways can you have 50¢ in change using only quarters, dimes and nickels?
    9·1 answer
  • Please help! 9/4(7+3-4*9)
    14·1 answer
  • Need help with math pls help me will mark brainiest.
    14·1 answer
  • Can someone help me with this math homework please!
    7·2 answers
  • What is the correct way to read 309.48
    14·2 answers
  • What is the cost of buying 10 tickets if 4 tickets cost 122 dollars?
    8·2 answers
  • MARKING BRAINLIST IF HELPFUL Write the equation of a line that passes through (3, 3) and perpendicular to a line that contains (
    5·1 answer
  • Do these look right?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!