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Effectus [21]
3 years ago
12

Help plssssssssssssssssss

Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0

Answer:

3) Not equivalent

4) Equivalent

5) Equivalent

(Multiply by two for the last two questions)

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Solve the following 3 × 3 system. Enter the coordinates of the solution below.
defon

9514 1404 393

Answer:

  (x, y, z) = (-1, 0, -3)

Step-by-step explanation:

We notice that the coefficients of z are such that elimination of the z term from the equations is made easy.

Adding equations 1 and 2:

  (2x -3y -2z) +(x +3y +2z) = (4) +(-7)

  3x = -3

  x = -1

Adding equations 2 and 3:

  (x +3y +2z) +(-4x -4y -2z) = (-7) +(10)

  -3x -y = 3

Substituting for x, we get ...

  (-3)(-1) -y = 3

 0 = y . . . . . . . . . . . add y-3 to both sides

Then z can be found from any equation. Substituting for x and y in the second equation gives ...

  -1 +2z = -7

  2z = -6 . . . . . add 1

  z = -3 . . . . . .divide by 2

The solution is (x, y, z) = (-1, 0, -3).

3 0
3 years ago
The area of a rectangular sandbox is (5x + 40) feet. Factor 5x + 40 to find possible
rjkz [21]

Answer: 5(x+8)

Step-by-step explanation:

5 0
3 years ago
If sin theta = cos theta then find the value of theta
Ksenya-84 [330]

Step-by-step explanation:

\because \sin  \theta =  \cos  \theta  \\   \\ \therefore \: \sin  \theta =  \sin(90 \degree -   \theta)  \\   \\ \therefore \:  \theta =  90 \degree -   \theta \\   \\ \therefore \:   \theta + \theta=  90 \degree \\  \\ \therefore \:  2\theta =  90 \degree \\  \\\therefore \:  \theta =   \frac{90 \degree }{2} \\  \\ \huge \orange{\boxed{\therefore \:   \theta =   45 \degree}}\\  \\

4 0
4 years ago
_____ less than a number is 51
Kryger [21]

Answer:

W number - blank is 51.

Step-by-step explanation:

I don't understand what the question is. What is the number unless you want something random then here:

Blank - 52

a number = 1

52 - 1 = 51

3 0
3 years ago
One-fourth of a number is 22. Find the number.
ruslelena [56]

Answer:

5.50

Step-by-step explanation:

I am smart

6 0
3 years ago
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