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Wittaler [7]
3 years ago
5

How would I solve for x?

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0
The Answer is Height: hb = 12.92<span>3

</span>Acute scalene triangle.<span>Sides: </span>a = 15 b = 13 c = 14

<span>Area: </span>T = 84
<span>Perimeter: </span>p = 42
<span>Semiperimeter: </span>s = 21

<span>Angle </span>∠ A = α = 67.38° = 67°22'49″ = 1.176<span> rad</span>
<span>Angle </span>∠ B = β = 53.13° = 53°7'48″ = 0.927<span> rad</span>
<span>Angle </span>∠ C = γ = 59.49° = 59°29'23″ = 1.038<span> rad</span>

<span>Height: </span>ha<span> = 11.2</span>
<span>Height: </span>hb<span> = 12.92</span>3 <- Answer
<span>Height: </span>hc<span> = 12</span>

<span>Median: </span>ma<span> = 11.23</span>6
<span>Median: </span>mb<span> = 12.97</span>1
<span>Median: </span>mc<span> = 12.16</span>6

<span>Inradius: </span>r = 4
<span>Circumradius: </span>R = 8.125

<span>Vertex coordinates: </span>A[14; 0] B[0; 0] C[9; 12]
<span>Centroid: </span>CG[7.667; 4]
<span>Coordinates of the circumcenter: </span><span>U[7; 4.125]</span>
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A tree casts a shadow 21m long. The angle of elevation of the sun is 55 degrees. What is the height of the tree?
Orlov [11]

Answer:

The height of the tree is about 30 feet.

Step-by-step explanation:

tan(55) = h/21

*21          *21

21*tan(55)=h

29.99=h

h=29.99=30 feet

4 0
3 years ago
What is 4(a5+7)+6(b7-5)
Andrej [43]
4a5+28+6b7-30
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(Is that 5a or a to the power of 5 )
20a+28+42b-30
20a+42b-2<—— this is 5a , 7b
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3 years ago
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Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=1%20%2B%201" id="TexFormula1" title="1 + 1" alt="1 + 1" align="absmiddle" class="latex-formula
marshall27 [118]

Answer:

2 and 3.

Step-by-step explanation:

1 + 1

Factor out.

2(1)

Multiply.

= 2

1 + 2

Add the terms.

= 3

8 0
3 years ago
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