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Anarel [89]
1 year ago
11

Are the expressions 8a - 3b - (2a + 4b) and 6a + b equivalent?

Mathematics
1 answer:
Margaret [11]1 year ago
3 0

Answer:

No.

Step-by-step explanation:

Let's start by simplifying the first expression:

8a-3b-(2a+4b)

Remove the parentheses:

8a-3b-(2a)-(4b)\\8a-3b-2a-4b

Combine like terms:

8a-2a-3b-4b\\6a-7b

6a-7b\neq 6a+b (Assuming that none of the variables are equivalent to 0)

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2 years ago
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
3 years ago
Imagine that * represents a new operation so that a * b means to double a, and then add b. For example, 2 * 10 = 14. What is -3
Rudik [331]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
1/2 (5-7x) = 8- 4x+6
Andre45 [30]
1/2(5-7x)=8-4x+6
-7/2x+5/2=-4x+14                       Simplify both sides
1/2x+5/2=14                               Add 4x to both sides
1/2x=23/3                                   Subtract 5/2 on both sides
2*(1/2x)=2*(23/2)                       Multiply both sides by 2
x=23 - Final Answer

                                             Cheers, Irys
7 0
2 years ago
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