Answer:
(A)
Step-by-step explanation:
From the given figure, we have to prove whether the two given triangles are congruent or similar.
Thus, From the figure, ∠3=∠4 (Vertically opposite angles)
Since, KL and NO are parallel lines and KO and LN are transversals, then
measure angle 1= measure angle 5 that is ∠1=∠5(Alternate angles).
Thus, by AA similarity rule, ΔKLM is similar to ΔONM.
Thus, Option A that is Triangle KLM is similar to triangle ONM because measure of angle 3 equals measure of angle 4 and measure of angle 1 equals measure of angle 5 is correct.
Answer:
0.5
Step-by-step explanation:
Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:

As h approaches 0 from the positive side, then:

Thus, f'(c) = 0
The sum of a polygon's angles are 540.
When you add all the angles together here, you get 456.
Now subtract 456 from 540.
540 - 456 = 84
The circles B and D are similar since the radius of the former is as twice as the radius of the latter.
<h3>Are the two circles shown in the figure similar?</h3>
By geometry we know that circles are defined by only one characteristic: radius. If two circles are similar, then the radii must be <em>different</em>. After a quick look at the figure, we conclude that the radii are
and
. Hence, the circles B and D are similar since the radius of the former is as twice as the radius of the latter.
To learn more on similarity: brainly.com/question/12670209
#SPJ1