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3 years ago

Im sorry im spamming but i really need help with this question, if someone could help please

Mathematics

1 answer:

Anni [7]3 years ago

5 0

Answer:

AB, BC and AC.

Step-by-step explanation:

The length of a side of a triangle is proportional to the angle across it.

Here the order of angles are, from smallest to largest, C, A and B.

The corresponding order of lengths (of the opposite sides) are therefore:

AB, BC and AC.

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Find the limit of the function by using direct substitution as X approaches one lim(x^2-8x -2)

Leno4ka [110]

Answer:

$lim_{x \to 1} x^2 -8x -2 =-9$

Step-by-step explanation:

For this case we want to find the following limit:

$lim_{x \to 1} x^2 -8x -2$

And we can find the limit distirbuting into each term like this:

$\lim_{x \to 1} x^2 -8 lim_{x \to 1} x -lim_{x \to 1} 2$

And replacing we got:

$1^2 - 8*1 -2 = 1-8-2 = -9$

So then the final answer for this case is:

$lim_{x \to 1} x^2 -8x -2 =-9$

8 0

4 years ago

Use the compound interest formula to compute the total amount accumulated and the interest eamed.

RideAnS [48]

Answer:

$12,137.39

Step-by-step explanation:

Use the Compound Amount formula:

A = P (1 + r/n)^(nt), where r is the interest rate as a decimal fraction, n is the number of times the interest is compounded each year, and t is the number of years.

Here, A = $9000(1 + 0.075/12)^(12*4), or

= $9000(1.3486) = $12,137.39

7 0

3 years ago

What is the name for fax like those in problem five

77julia77 [94]

To answer you need to show question 5

7 0

3 years ago

Someone pls help! <br> write the expression in radical form. 2 4/5

kipiarov [429]

Answer:

$\sqrt[5]{2^4}$

Step-by-step explanation:

Maybe you want 2^(4/5) in radical form.

The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.

$2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}$

In many cases, it is preferred to keep the power inside the radical symbol.

7 0

3 years ago

A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes meter at a sp

Natali [406]

Answer:

Given:

length of the wire = 0.20 meters

magnetic field strength = 0.45 newtons/amperes meter

speed = 10.0 meters per second

emf = B * l * v

B = flux density ; l = length of the wire ; v = velocity of the conductor

emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds

emf = 0.90 volts

The emf produced is 0.90 volts.

Step-by-step explanation:

6 0

3 years ago