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Aliun [14]
3 years ago
9

Suppose that 8% of the general population has a disease and that the test for the diesease is accurate 70% of the time. What is

the probability of testing positive for the disease
Mathematics
1 answer:
balu736 [363]3 years ago
8 0

Answer:

P = 0.332

Step-by-step explanation:

The probability of having the disease is 0.08

The probability that the test predicts with accuracy is 0.7.

We need to find the probability that the test positive for the disease.

Several cases may occur.

Case 1.

You have the disease and the test predicts it accurately

P_1 = 0.08(0.7) = 0.056

Case 2

You do not have the disease and the test predicts that you have it

P_2 = 0.92(0.3) = 0.276

Then the probability that the test predicts that you have the disease is the union of both probabilities P1 and P2

P = P_1 + P_2\\\\P = 0.056 + 0.276\\\\P = 0.332

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Slope of 1,-7 and -3-4​
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\large \mathfrak{Solution : }

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4 0
3 years ago
If f'(x) = 12x^3 - 2x^2 - 17 and f(1) = 8 , find f(x).
Cloud [144]

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To find f'(x), we will follow the steps below:

We will start by integrating both-side of the equation

∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx

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7 0
3 years ago
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Allushta [10]
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I hoped this helped! :)

8 0
3 years ago
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