Let l, t, b represent the numbers of lions, tigers, bears, respectively.
2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals
_____
The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
Answer:
Step-by-step explanation:
Given that a parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and at entrance II according to a Poisson distribution at an average of 2 per hour.
Assuming the number of cars arriving at the two parking lots are independent we have total number of cars arriving X is Poisson with parameter 3+2 = 5
X is Poisson with mean = 5
the probability that a total of 3 cars will arrive at the parking lot in a given hour
= P(X=3) = 0.1404
b) the probability that less than 3 cars will arrive at the parking lot in a given hour
= P(X<3)
= P(0)+P(1)+P(2)
= 0.1247
For one it would be c and d
Two x is greater than seven
three would be x is greater than or equal to 6
Four would be subtract eight from both sides you get 24 and then divide by negative four which gets you negative six but then you have to turn the sign around. Number set would be anything above negative six,so like negative five, 52, and one
Five would be subtract 3 from both sides giving you 5 on the right side and then multiply by six on both sides giving you thirty on the right side, resulting in x is greater than or equal to thirty. Three numbers that would work would be thirty, fifty nine, and thirty five.
The answer will be 7x^2 + 5x
