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blsea [12.9K]
2 years ago
14

Answer this question fast with steps and I'll mark brilliantest​

Mathematics
1 answer:
zvonat [6]2 years ago
7 0

Answer:

825g and 3108g respectively

Step-by-step explanation:

Nitrogen needed for 2kg compound=275g

Nitrogen needed for 6kg compound=825g

Sulphur needed for 2kg compound=1036g

Sulphur needed for 6kg compound=3108g

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Solving rational equations<br><br> solve for x: 3/x-4=7/x
KIM [24]

Solving the rational equation \frac{3}{x-4}=\frac{7}{x} the value of x is 7

Step-by-step explanation:

We need to solve rational equation: \frac{3}{x-4}=\frac{7}{x} and find value of x.

Solving:

\frac{3}{x-4}=\frac{7}{x}

Cross multiplying:

3(x)=7(x-4)\\Simplifying:\\3x=7x-28\\3x-7x=-28\\-4x=-28\\x=-28/-4\\x=7

So, value of x = 7.

Solving the rational equation \frac{3}{x-4}=\frac{7}{x} the value of x is 7

Keywords: Solving the rational equation

Learn more about Solving the rational equation at:

  • brainly.com/question/13168205
  • brainly.com/question/1757979
  • brainly.com/question/2456302

#learnwithBrainly

8 0
2 years ago
Read 2 more answers
would someone be able to explain to me how to solve these problems? I don't need the solutions, I just need an explanation. I ne
Leni [432]
The first 3  are examples of the difference of 2 squares so you use the identity 
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0 
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7  and 7.
Number 7 reduces to 3x^2 =12, x^2  = 4 so x = +/- 2
Number 8  take out GCf (d) to give 
d(d - 2)  = 0   so d = 0 ,  2
9 and 10 are more difficult to factor
you use the 'ac' method  Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end 
that is 2 * 2 =  4
Now we want  2 numbers  which when multiplied give + 4 and when added give - 5:-    -1 and -4  seem promising so we write the equation as:-

2x^2 - 4x - x + 2 = 0

now factor by grouping 
2x(x - 2) - 1(x - 2) = 0

(x - 2) is common so

(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0  and now you can find x.

The last example is solved in the same way.


8 0
3 years ago
A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.
Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

t=\sqrt{\frac{2h}{a}} ,where h=height of release

a=acceleration

a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}

Where I=moment of inertia

a for hoop

a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}

a=\frac{g\sin \theta }{2}

a for Uniform solid cylinder

a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}

a=\frac{2g\sin \theta }{3}

a for spherical shell

a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}

a=\frac{3g\sin \theta }{5}

a for Uniform Solid

a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}

a=\frac{5g\sin \theta }{7}

time taken will be inversely proportional to the square root of acceleration

t_1=k\sqrt{2}=1.414k

t_2=k\sqrt{\frac{3}{2}}=1.224k

t_3=k\sqrt{\frac{5}{3}}=1.2909k

t_4=k\sqrt{\frac{7}{5}}=1.183k

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0
3 years ago
Hewp..Pls
timofeeve [1]

Answer:

2y+4x=12

2*1+4*8=12

2+32=12

35=12

7 0
3 years ago
Could I get help on this question
forsale [732]
The answer is 500 becuase it is
5 0
3 years ago
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