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weqwewe [10]
2 years ago
9

Add. -6.3+(-9.7) - 6.3+(-9.7) = (Type an integer or a decimal.)

Mathematics
1 answer:
vlada-n [284]2 years ago
3 0
7.6992 buds no sis
BDIS yes yes teye what they said
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Pls answer ASAP I need help
gavmur [86]

Answer:

g=1.5

Step-by-step explanation:

-0.4+0.9=0.5

0.5*3 1.5

6 0
3 years ago
In circle O, m∠R = 30.8°. Find m∠NOQ.
nordsb [41]

Given:

In circle O, m∠R = 30.8°.

To find:

The m∠NOQ

Solution:

Central angle theorem: According to this theorem, the central angle is always twice of subtended angle on the same arc.

Angle NOQ and angle NRQ are on the same arc but ∠NOQ is the central angle and ∠NRQ is the subtended angle on the arc NQ.

Using central angle theorem, we get

m\angle NOQ=2\times m\angle NRQ

m\angle NOQ=2\times m\angle R

m\angle NOQ=2\times 30.8^\circ

m\angle NOQ=61.6^\circ

Therefore, m\angle NOQ=61.6^\circ.

4 0
3 years ago
Plss show the work<br> –4z + 8 = –2z
IceJOKER [234]

Answer:

z=-4/3

Step-by-step explanation:

8=-6z

z=-8/6

z=-4/3

4 0
2 years ago
The graph of the function f (x) is shown below. When f(x)=0,x=?
IgorLugansk [536]

Answer:

0

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
For 300 trading​ days, the daily closing price of a stock​ (in $) is well modeled by a Normal model with mean ​$196.99 and stand
KATRIN_1 [288]

Answer:

a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

Step-by-step explanation:

For a) b) and c) we will use the empirical rule, so, we can observe the image shown below

a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%  

b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%

c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.

d) The z-score related to 208 is z_{1} = (208-196.99)/7.12 = 1.5 and the z-score related to 185 is  z_{2} = (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

5 0
3 years ago
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