PLEASEE HELPP MEEE WITH NUMBERSSS 6 AND 7 PLEASSEEE HELPP IM STUGGLING WITH THIS!!!!!!!!

Mathematics

1 answer:

choli [55]3 years ago

3 0

Answer:

hi dont report me we are friends can i get brainliest plzz?

Step-by-step explanation:

You might be interested in

Factor 4x^4+7x^2-2=0

natulia [17]

Answer:

(2x-1)(2x+1)(x^2+2) = 0

Step-by-step explanation:

Here's a trick: Use a temporary substitution for x^2. Let p = x^2. Then 4x^4+7x^2-2=0 becomes 4p^2 + 7p - 2 = 0.

Find p using the quadratic formula: a = 4, b = 7 and c = -2. Then the discriminant is b^2-4ac, or (7)^2-4(4)(-2), or 49+32, or 81.

Then the roots are:

-7 plus or minus √81

p= --------------------------------

p = 2/8 = 1/4 and p = -16/8 = -2.

Recalling that p = x^2, we let p = x^2 = 1/4, finding that x = plus or minus 1/2. We cannot do quite the same thing with the factor p= -2 because the roots would be complex.

If x = 1/2 is a root, then 2x - 1 is a factor. If x = -1/2 is a root, then 2x+1 is a factor.

Let's multiply these two factors, (2x-1) and (2x+1), together, obtaining 4x^2 - 1. Let's divide this 4x^2 - 1 into 4x^4+7x^2-2=0. We get x^2+2 as quotient.

Then, 4x^4+7x^2-2=0 in factored form, is (2x-1)(2x+1)(x^2+2) = 0.

6 0

2 years ago

PLZ HELP, 20 pts and brainliest awarded, plz ASAP!!!!!! see image below

Amiraneli [1.4K]

Answer:

Option B

Step-by-step explanation:

we have

$f(x)=x^{3}-x^{2}-9x+9$

we know that

The vertical line test is a visual way to determine if a curve is a function or not. A function can only have one value of y for each unique value of x

In this problem

The given function passes the vertical line test

therefore

f(x) is a function

The Horizontal Line Test is a test use to determine if a function is one-to-one

If a horizontal line intersects a function's graph more than once, then the function is not one-to-one.

In this problem

The given function fails the horizontal line test

because for f(x)=0 x=-3, x=-1, x=3

therefore

It is no a one-to-one function

8 0