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amm1812
3 years ago
15

Which number line can be used to find the distance between (4, -1) and (8. - 1)?

Mathematics
1 answer:
____ [38]3 years ago
8 0
I don’t really no this answer? Sorry
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Can someone please help me?
VikaD [51]

Answer:

The answer is 27

Step-by-step explanation:

The reason being, you can solve this 2 ways.

1) Combine like terms, 7a-4a = 3a.

Now just substitute (a=9) into 3a.

3 * (9) = 27.

2) Or just substitute a = 9 into the original expression.

7 * (9) - 4 * (9)

= 63 - 36 = 27

4 0
2 years ago
Read 2 more answers
If the sum of two prime numbers is 999 what is their product
abruzzese [7]
999.999 because if one is 99 the other would make it 9999
7 0
3 years ago
A. The point-slope form of the equation of a line is y ? y1 = m(x ? x1), where m is the slope and (x1, y1) is a point on the lin
Rudiy27

Answer:

A.

y - 5 = -2(x-6)

Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.

Then apply point-slope form.

B. The answer is x = 6.

The midpoint of JK is

\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{8+ 4}{2}, \frac{4 + 4}{2} \right) = \left(6,4\right)

The line that goes through JK is just a horizontal line y = 4 because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is, x = 6.

8 0
3 years ago
Someone please help with 9th question !!!!
meriva

LIMITS  \:  \: AND \:  \:  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  DERIVATIVES


Heya !

Check the attachment.
Hope it helps you :)

5 0
3 years ago
a survey of students in a school showed 1/2 of the students exercise regularly, 2/5 of the students exercise occasionally and th
Sveta_85 [38]

Answer:

1/10

Step-by-step explanation:

add 2/5 and 1/2 then subtract from 1 whole to find the remainder

make it so they have the same denominator

2/5 = 4/10

1/2 = 5/10

4/10 + 5/10 = 9/10

1=10/10

10/10-9/10 = 1/10

so 1/10 of the students don't exercise at all

5 0
3 years ago
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