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tekilochka [14]
3 years ago
15

SHOW WORK I’ll mark you brainlist

Mathematics
1 answer:
dangina [55]3 years ago
5 0

Answer:

y=-2x+11 i believe :)....

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Using Euler's relation, derive the following relationships:a. Cosθ=½(e^jθ+e^−jθ)b. Sinθ=½(e^jθ−e(^−jθ)
Montano1993 [528]

Answer:

a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]

Step-by-step explanation:

a.We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Adding both equations, we have

e^jθ = cosθ + jsinθ

+

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ

Simplifying, we have

e^jθ + e^(-jθ) = 2cosθ

dividing through by 2 we have

cosθ = ¹/₂[e^jθ + e^(-jθ)]

b. We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Subtracting both equations, we have

e^jθ = cosθ + jsinθ

-

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)

Simplifying, we have

e^jθ - e^(-jθ) = 2jsinθ

dividing through by 2 we have

sinθ = ¹/₂[e^jθ - e^(-jθ)]

4 0
4 years ago
UGH these math problems tho please help!
Dovator [93]

Answer:

#6 would be 15/7

#7 would be 4/90

#8 would be 17/12

i can't see number 9

#11 would be 65/15 or 4.3333333


31 + 34

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Help!giving brainliest and 30 points
eduard

Answer:

D 80

Step-by-step explanation:

step by step

350 +(-350)=0 + 5h = 750 + (-350) =400

5h/5 =400/5=80

h=80

7 0
3 years ago
The angles of a quadrilateral are 140, 80, 60, and 80<br> What type of quadrilateral could it be?
My name is Ann [436]
Your answer is a trapezium 
5 0
3 years ago
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2.57 as a improper fraction
USPshnik [31]

Answer: 2 57/100 hope that helps

6 0
3 years ago
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