All categories

2 years ago

Please help 3/4 Solve the binomial (2ab-3c)(2ab+3c)

Mathematics

2 answers:

german2 years ago

5 0

Answer:

I’m answering so the other peep can get brainliest she’s correct I think I’m pretty sure I think so thx for points have a great day byee

Step-by-step explanation:

Pani-rosa [81]2 years ago

4 0

ANSWER:

(2ab - 3c)(2ab + 3c)

Using identity (a + b)(a - b) = a² - b².

(2ab)² - (3c)²

4a²b² - 3c².

You might be interested in

Question 8 of 10 What is sin 30º? 60 2 901 D A B. c.. () E. E )

levacccp [35]

Answer:

A. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

<u>Trigonometry</u>

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] sinθ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

sin 30°

<u>Step 2: Solve</u>

Since sin is opposite over hypotenuse, we need to find the length of the opposite leg of the angle and the length of the hypotenuse.

Given the triangle and it's values, the opposite leg to the 30° angle is 1 and the hypotenuse is 2.

Substituting it into sin, we have:

sin 30° = 1/2 = 0.5

∴ our answer is A.

3 0

2 years ago

Help please!!

IRINA_888 [86]

I think it’s QT EJ and HA

7 0

3 years ago

Read 2 more answers

Helppp this is chemistry not math though

Scorpion4ik [409]

Answer:

It is balance she need to use. Answer is B.

7 0

3 years ago

Read 2 more answers

Real world situation for 834+14s>978-10s

liraira [26]

834+14s=848>978-10s=968

a real life situation for that could be like how many apples 848apples/968total

6 0

3 years ago

Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).

Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>

The critical points of a function are the values of x for which:

$f^{\prime}(x) = 0$

In this problem, the function is:

$f(x) = x^3 + ax^2 + b$

Hence, the derivative is:

$f^{\prime}(x) = 3x^2 + 2ax$

Then:

$f^{\prime}(x) = 0$

$3x^2 + 2ax = 0$

$x(3x + 2a) = 0$

$x = 0$

$3x + 2a = 0$

$3x = -2a$

$x = -\frac{2a}{3}$

Since the critical point is at x = 2, we have that:

$-\frac{2a}{3} = 2$

$-2a = 6$

$2a = -6$

$a = -3$

Then:

$f(x) = x^3 - 3x^2 + b$

Critical point at (2,3) means that when $x = 2, y = 3$ , then:

$3 = 2^3 - 3(2)^2 + b$

$8 - 12 + b = 3$

$b = 7$

You can learn more about the critical point concept at brainly.com/question/2256078

4 0

2 years ago