All categories

3 years ago

Find the equation of the axis of symmetry of the following parabola algebraically: y=-5x²+20x

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

x= 2

Step-by-step explanation:

hello :

y= -5x²+20x a= -5 b= 20

the axis symmetry is the line when an equation is : x = -b/2a

x= -(20)/2(-5)

x= 2

You might be interested in

F(1) = 4, f(n) = f(n − 1) + 11

zvonat [6]

Answer:

Step-by-step explanation:

You don't specify what you're supposed to do, so I'll make an educated guess.

Given the sequence f(1) = 4, f(n) = f(n − 1) + 11, find the first 5 terms:

f(1) = 4

f(2) = f(2 - 1) + 11 = f(1) + 11 = 4 + 11 = 15

f(3) = f(2) + 11 = 15 + 11 = 26

f(4) = f(3) + 11 = 26 + 11 = 37

f(5) = 37 + 11 = 48

4 0

3 years ago

Help please very much

Norma-Jean [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

Find the value of y so that line is passing through two points

Alenkinab [10]

Slope of a line passing through two given points
= (y2-y1)/(x2-x1)

For m=3, and substituting coordinates,
3=(1-y)/(4-1)
solve for y
1-y=3*3=9
y=1-9=-8

Answer: y=-8

6 0

3 years ago

Suppose you rolled a twelve-sided number cube instead of a standard six-sided one. How would the probability of these events cha

BlackZzzverrR [31]

Answer:

Decrease

Increase

Does not change

5 0

3 years ago

Read 2 more answers

Billie solved the equation below by completing the square, but she got the incorrect solution. In which step did Billie first ma

Tanzania [10]

Answer:

step 2

Step-by-step explanation:

we have

$x^{2} +10x-49=0$ ---> given problem

step 1

Move the constant to the right side

$x^{2} +10x=49$

the step 1 is correct

step 2

Complete the square

$x^{2} +10x+5^2=49+5^2$

$x^{2} +10x+5^2=74$

The step 2 is not correct

step 3

Rewrite as perfect squares

$(x+5)^{2}=74$

step 4

take square root both sides

$x+5=\pm\sqrt{74}$

step 5

Find the values of x

$x=-5\pm\sqrt{74}$

$x=-5+\sqrt{74}$

$x=-5-\sqrt{74}$

5 0

3 years ago