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Marta_Voda [28]
2 years ago
13

Evaluate this expression: Write only the answer.*12 X (3 + 22) - 2 - 10Your answer​

Mathematics
1 answer:
tester [92]2 years ago
7 0

Answer:

288

Hope this helps :)

You might be interested in
Which of the following is equivalent to cos x?
Otrada [13]

ANSWER

D) sin Y

EXPLANATION

The given triangle is a right triangle.

This implies that that:

x + y = 90 \degree

Then we have

y= 90 - x

Recall that

\cos(x)  =  \sin(90 - x)

But

90 - x = y

When we do the substitution, we get,

\cos(x)  =  \sin(y)

Therefore cos(x) is a equivalent to sin(y).

The correct answer is D.

3 0
3 years ago
4x^2 +3x-11y+17
masha68 [24]

Answer:

1) 4x^2, 3x, -11y, 17 (4 terms)

2) 4, 3, -11, 17 (4 coefficients)

3) none

Step-by-step explanation:

3 0
3 years ago
Subtract and reduce: 2 2/3 - 1 1/2
babunello [35]

Step-by-step explanation:

I used a calculator but the answer is 1 1/6

5 0
2 years ago
Decide whether the equations is a trigonometric function identity, EXPLAIN.
hodyreva [135]

(1) Answer: Identity true

\cos^2x(1+\tan^2x)=\cos^2x(1+\frac{sin^2x}{cos^2x})=\\= \cos^2x\frac{cos^2x+sin^2x}{cos^2x}=1

(2) Answer: Identity true

\sec x \tan x(1-\sin^2x)=\sin x\\\frac{1}{\cos x}\frac{\sin x}{\cos x}(\cos^2x)=\sin x\\\sin x = \sin x


(3) Answer: Identity true

\sin^2(\theta)\csc^2(\theta)=\sin^2(\theta)+\cos^2(\theta)\\\sin^2(\theta)\frac{1}{\sin^2(\theta)}=\sin^2(\theta)+\cos^2(\theta)\\1 = 1


7 0
3 years ago
In testing a certain kind of missile, target accuracy is measured by the average distance X at which the missile explodes. The d
3241004551 [841]

Answer:

The answer is c) 761.0

Step-by-step explanation:

Mathematical hope (also known as hope, expected value, population means or simply means) expresses the average value of a random phenomenon and is denoted as E (x). Hope is the sum of the product of the probability of each event by the value of that event. It is then defined as shown in the image, Where x is the value of the event, P the probability of its occurrence, "i" the period in which said event occurs and N the total number of periods or observations.

 The variance of a random variable provides an idea of the dispersion of the random variable with respect to its hope. It is then defined as shown in the image.

Then you first calculate E [x] and E [x^{2}], and then be able to calculate the variance.

E[x]=0*\frac{1}{40} +10*\frac{1}{20} +50*\frac{1}{10} +100*\frac{33}{40}

E[x]=0+\frac{1}{2} +5+\frac{165}{2}

E[X]=88

So <em>E[X]²=88²=7744</em>

On the other hand

E[x^{2} ]=0^{2} *\frac{1}{40} +10^{2} *\frac{1}{20} +50^{2} *\frac{1}{10} +100^{2} *\frac{33}{40}

E[x²]=0+5+250+8250

<em>E[x²]=8505 </em>

Then the variance will be:

Var[x]=8505-7744

<u><em>Var[x]=761 </em></u>

5 0
3 years ago
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