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liq [111]
2 years ago
11

Pls just give coordinate points i will give brainliest

Mathematics
1 answer:
Inga [223]2 years ago
5 0

Answer:

sorry i dont know

Step-by-step explanation:

hope you find somone :D

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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
3 years ago
Read 2 more answers
Given X(0, 2), Y(-2, 2), and Z(-2, 0), find the coordinates of X', Y', and Z' after a dilation with scale factor -4. ​
kotykmax [81]

Answer:

what is the origin of the dilation?

3 0
3 years ago
►
n200080 [17]

Answer:

both population and sample

Step-by-step explanation:

3 0
3 years ago
Multiply and simplify. <br><br> 2/3 * (1/3 + 3 1/4)=?
kondor19780726 [428]
<span>2/3 </span>×<span> (1/3 + 3 1/4)
= 2/3 (1/3 + 13/4)
= 2/3 (43/12)
= 43/18
= 2 7/18</span>
5 0
3 years ago
Read 2 more answers
Which function grows the fastest for large values of x? f(x)=8x f(x)=3x f(x)=4x2+3 f(x)=1.5x 20 points
Aleonysh [2.5K]
The 4 functions are:
f_1 (x) = 8x
f_2(x)=3x
f_3(x)=4x^2+3
f_4(x)=1.5 x

Let's keep in mind that for large values of x, a quadratic function grows faster than a linear function:
ax^2 \ \textgreater \  kx for large values of x

In this problem, we can see that the only quadratic function is f_3(x), while all the others are linear functions, so the function that grows faster for large values of x is
f_3(x) = 4x^2 +3
7 0
3 years ago
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