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Natasha2012 [34]
3 years ago
15

Solve for x 4x+15=71

Mathematics
2 answers:
Ilya [14]3 years ago
7 0

Answer:

x=14

Step-by-step explanation:

4x +15 =71

4x =71 - 15

4x =56

x=56 :4

x=14

4 ×14 +15 =71

56 +15 =71

71 =71

MaRussiya [10]3 years ago
4 0

Answer: X=14

Step-by-step explanation: Plug 14 in for x. 4*14 equals 56. 56+15 equals 71. and 71=71.

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The neq coordinates would be -8,8 and 8,-8
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Which equation is NOT an identity?
Simora [160]

Answer:

D

Step-by-step explanation:

If you add 0 to anything, you do not have anything new when you are finished. A is an identity.

When you multiply 1 times anything, you do not get anything new. B is an identity

When you switch the order of two numbers and they are not affected by signs, then you are using the commutative property of addition. Nothing changes. C is an identity.

D is the problem child. Nothing I can think of right now will not change will you add 1 to it. If you can think of something that doesn't change when you add one to it, please put it in the comments. Otherwise, D is not an identity.

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3 years ago
In a television series there is exactly one crime committed in every episode. It has been observed that the probability that the
Rama09 [41]

Answer:

P(x \le 3) = 0.2352

Step-by-step explanation:

Given

p = 0.35 --- male committing a crime in an episode

n = 5 -- Number of episodes

Required

Determine the probability of male committing a crime at least 3 times

This question illustrates binomial distribution and will be solved using;

P(x) = ^nC_x * p^x * (1 - p)^{n-x

So, the required probability is represented as:

P(x \ge 3)

And will be calculated using:

P(x \ge 3) = P(x = 3) + P(x = 4) + P(x = 5)

P(x = 3) = ^5C_3 * (0.35)^3 * (1 - 0.35)^{5-3}

P(x = 3) = ^5C_3 * (0.35)^3 * (1 - 0.35)^2

P(x = 3) = 10 * (0.35)^3 * (0.65)^2

P(x = 3) = 0.1811

P(x = 4) = ^5C_4 * (0.35)^4 * (1 - 0.35)^{5-4}

P(x = 4) = 5 * (0.35)^4 * (1 - 0.35)^1

P(x = 4) = 5 * (0.35)^4 * (0.65)

P(x = 4) = 0.0488

P(x = 5) = ^5C_5 * (0.35)^5 * (1 - 0.35)^{5-5}

P(x = 5) = 1 * (0.35)^5 * (1 - 0.35)^0

P(x = 5) = 1 * (0.35)^5 * (0.65)^0

P(x = 5) = 1 * (0.35)^5 * 1

P(x = 5) = 0.0053

So:

P(x \ge 3) = P(x = 3) + P(x = 4) + P(x = 5)

P(x \le 3) = 0.1811 + 0.0488 + 0.0053

P(x \le 3) = 0.2352

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3 years ago
Is 3/5 greater or less than 1/4
JulsSmile [24]
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4 years ago
Read 2 more answers
g Suppose that a die is rolled twice. What are the possible values that thefollowing random variables can take on:(a) the maximu
KengaRu [80]

Answer:

(a) A = {1, 2, 3, 4, 5, 6}

(b) B = {1, 2, 3, 4, 5, 6}

(c) C = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(d) D = {-5, -4, -3, -2, -1, -0, 1, 2, 3, 4, 5}

Step-by-step explanation:

Assume each roll can result in the numbers 1, 2, 3, 4, 5, or 6.

(a) If both rolls result in a 1, the maximum value is 1. If either roll results in a 6, the maximum value is 6; all integers between 1 and 6 are also possible. Therefore, the possible values are:

A = {1, 2, 3, 4, 5, 6}

(b) If either roll results in a 1, the minimum value is 1. If both rolls result in a 6, the minimum value is 6; all integers between 1 and 6 are also possible. Therefore, the possible values are:

B = {1, 2, 3, 4, 5, 6}

(c) If both rolls result in a 1, the sum is 2. If both rolls results in a 6, the sum is 12; all integers between 2 and 12 are also possible. Therefore, the possible values are:

C = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(d) If the first roll results in a 1 and the second results in a 6, the result is -5. On the other hand, if the first roll results in a 6 and the second results in a 1, the result is 5; all integers between -5 and 5 are also possible. Therefore, the possible values are:

D = {-5, -4, -3, -2, -1, -0, 1, 2, 3, 4, 5}

7 0
3 years ago
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