Answer:
18
Step-by-step explanation:
=2(cot²A+1)
=2cosec²A. [` . ` cot²A+1=cosec²A] =2(1/sinA)²
[' . 'cosecA=1/sinA]
=2×3²/1
=2cot²a+2=2×8+2=16+2=18
What is the interquartile range of the following data set? 45,12,48,96,61,84,29,1,72,5,14
slava [35]
Answer:
60
Step-by-step explanation:
Population size : 11
To calculate inter-quartile range
- Order the data from least to greatest.
- Calculate the median of both the lower and upper half of the data.
- The IQR is the difference between the upper and lower medians.
Step 1
1, 5 , 12 ,14 , 29 , 45 , 48, 61 , 72 , 84 , 96
Step 2
medium = 45
Step 3
Q1
1 , 5 , 12 ,14 , 29
median = 12
Q3
48 , 61 , 72 , 84 , 96
median = 72
Step 4
IQ = Q3 - Q1
= 72 - 12
= 60
They both used the same amount. 6/8 when simplified is the same as 3/4.
Answer:
64
Step-by-step explanation:
