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noname [10]
2 years ago
12

A timer is started and a few moments later a swimmer dives into the water and then comes back up. The swimmer’s depth (in feet)

as a function of time (in second after time was started) is given by the equation h(t)=t^2- 16t + 55
Rewrite the formula and select each true statement below.

Options:
The swimmer dives into the water 5 seconds after the timer is started.

The swimmer reaches a maximum depth of 16 feet.

The swimmer comes back up 16 second after the timer is started.

The swimmer comes back up 11 second after the timer is started.

This function shows that the swimmer dives into the water two separate times.
Mathematics
1 answer:
zhannawk [14.2K]2 years ago
6 0

Answer: The swimmer dives into the water 5 seconds after the timer is started.

The swimmer comes back up 11 seconds after the timer is started.

Step-by-step explanation:

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Describe how the digits shift when you multiply a number by 0.1.
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Answer:

they move one over to the left

Step-by-step explanation:

a zero is added to the number and the decimal is shifted


3 0
3 years ago
PLEASE HELP ME!
lawyer [7]
At the beining, he has 76
that is at x=0
y=mx+76

find m
given
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find m

100=2m+76
minus 76 both sides
24=2m
divide both sides by 2
12=m

the equatin is

y=12x+76
6 0
3 years ago
4/5 + 2 /5 ÷ 2/ 3(they are fractions)PLEASE HURRY
chubhunter [2.5K]

Answer:

1.4 or in fraction form 7/5

Step-by-step explanation:

Hope this is what you were looking for

4 0
3 years ago
Is f(x)=e^2 an exponential function? If so what is its base? If not, why?
makkiz [27]

Answer:

No. It is a constant function.

Step-by-step explanation:

The function f(x) = e^2 is not an exponential functional. Rather, it is a constant function. The reason for this is that in f(x) = e^2, there is no x involved on the right hand side of the equation. The approximate value of e is 2.718281, and the approximate value of 2.718281^2 is 7.389051. This means that f(x) = e^2 = 7.389051. It is important to note that for any value of x, the value of the function remains fixed. This is because the function does not involve the variable x in it. The graph of the function will be a line parallel to the x-axis, and the y-intercept will be 7.389051. For all the lines parallel to x-axis, the value of the function remains the same irrespective of the value of x. Also, the derivative of the function with respect to x is 0, which means that the value of the function is unaffected by the change in the value of x!!!

6 0
3 years ago
Write a point slope form of the line through point J(4,1) with slope -5
mrs_skeptik [129]
Y - y1 = m(x - x1)
slope(m) = -5
(4,1)...x1 = 4 and y1 = 1
now we sub
y - 1 = -5(x - 4) <===
4 0
3 years ago
Read 2 more answers
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