The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:
![\mathbf{h(t) = -16t^2 + 160t}](https://tex.z-dn.net/?f=%5Cmathbf%7Bh%28t%29%20%3D%20-16t%5E2%20%2B%20160t%7D)
Differentiate the function with respect to t
![\mathbf{h'(t) = -32t + 160}](https://tex.z-dn.net/?f=%5Cmathbf%7Bh%27%28t%29%20%3D%20-32t%20%2B%20160%7D)
Set to 0
![\mathbf{h'(t) = -32t + 160 = 0}](https://tex.z-dn.net/?f=%5Cmathbf%7Bh%27%28t%29%20%3D%20-32t%20%2B%20160%20%3D%200%7D)
So, we have:
![\mathbf{-32t + 160 = 0}](https://tex.z-dn.net/?f=%5Cmathbf%7B-32t%20%2B%20160%20%3D%200%7D)
Collect like terms
![\mathbf{-32t =- 160 + 0}](https://tex.z-dn.net/?f=%5Cmathbf%7B-32t%20%3D-%20160%20%2B%200%7D)
![\mathbf{-32t =- 160}](https://tex.z-dn.net/?f=%5Cmathbf%7B-32t%20%3D-%20160%7D)
Solve for t
![\mathbf{t = \frac{- 160}{-32}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bt%20%3D%20%5Cfrac%7B-%20160%7D%7B-32%7D%7D)
![\mathbf{t = 5}](https://tex.z-dn.net/?f=%5Cmathbf%7Bt%20%3D%205%7D)
Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
brainly.com/question/6636648
Answer:
380ft
Step-by-step explanation:
Assuming the balloon rises 525ft from sea level (0ft), all we need to do is subtract both numbers to find the new height.
525 - 145 = 380ft
There could be many different scenarios though because if the question provides the height of land off sea level, you would have to take that into account as well.
Best of Luck!
Answer:
Yes: this a fraction so the increase by a multiple of 10x does not change the value of 0.8 for option one being largest.
Step-by-step explanation:
<span>If you are given a tetherball swinging in a horizontal circle around a pole attached with a 1.2m long massless rope and it makes an angle of 40 degrees with the pole, you will have a velocity of the ball moving at 0.84m/s.</span>