Answer: point C = (3.75, 1.5)
Step-by-step explanation:
As the direction of the distance is from A to B, we need to down the y-axis and along (to the right) the x-axis.
Find the distance between the x-coordinates of both points by subtracting the x-coordinate of A from the x-coordinate of B:
5 - 0 = 5
3/4 of the length of this distance = 0.75 x 5 = 3.75
So the x-coordinate of C will be the sum of the distance (3.75) and the x-coordinate of A (as we are "travelling" from A to B):
3.75 + 0 = 3.75
Find the distance between the y-coordinates of both points by subtracting the y-coordinate of B from the y-coordinate of A:
3 - 1 = 2
3/4 of the length of this distance = 0.75 x 2 = 1.5
So the y-coordinate of C will be the y-coordinate of A minus the distance (1.5):
3 - 1.5 = 1.5
Therefore, point C = (3.75, 1.5)
Hope that helps - i dont know what u meant by option 1,2,3 so if u have an questions or i did it wrong i will fix it <3
Answer:
A. width = x - 4.5
B. 111 = 2(x + (x -4.5))
Step-by-step explanation:
A. The width is 4.5 meters shorter than x, so is x -4.5.
__
B. The perimeter is twice the sum of length and width. It is 111 meters, so an equation for it could be ...
111 = 2(x + (x -4.5))
Answer:
assuming you're asking whats g(2+3) the answer is 40
Step-by-step explanation:
8(2+3)
8(5)
8 x 5 = 40
:))
Answer:
Approximately 
(
.) (Assume that the choices of the 
passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 
floors.)
Step-by-step explanation:
If there is no requirement that no two passengers exit at the same floor, each of these passenger could choose from any one of the floors. There would be a total of 
unique ways for these 
passengers to exit the elevator.
Assume that no two passengers are allowed to exit at the same floor.
The first passenger could choose from any of the floors.
However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only 
floors.
Likewise, the third passenger would have to choose from only 
floors.
Thus, under the requirement that no two passenger could exit at the same floor, there would be only 
unique ways for these two passengers to exit the elevator.
By the assumption that the choices of the passengers are independent and uniform across the floors. Each of these 
combinations would be equally likely.
Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:
.
