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3 years ago

P(x)=1/2(x-2)(x-3)(x+7) find the constant

Mathematics

1 answer:

SashulF [63]3 years ago

8 0

Answer:

Step-by-step explanation:

p(x)=1/2(x-2)(x-3)(x+7)

costant term=1/2(-2)(-3)(7)=21

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WILL MARK AS BRAINIEST IF RIGHT

Andre45 [30]

Answer:

Step-by-step explanation:

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3 years ago

Point A’ is the image of Point A when point A is rotated about the origin B. What angle in the counterclockwise direction is A r

liberstina [14]

Answer:

90 degrees

Step-by-step explanation:

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3 years ago

Noah finds an expression for V(x) that gives the volume of an open-top box in cubic inches in terms of the length x in inches of

11111nata11111 [884]

SOLUTION

Given the question on the question tab;

$From\text{ the graph; we will trace from x=1 upward to meet the curve, then trace to the y-axis.}$

The trace on the graph is given below;

$The\text{ value of y when x=1 is 15.}$

Final answer:

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1 year ago

How do solve you do 5b/2=27.5

inna [77]

2.5 b = 27.5
b = 27.5 / 2.5

b = 11

6 0

3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

3 years ago