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gregori [183]
3 years ago
13

P(x)=1/2(x-2)(x-3)(x+7) find the constant

Mathematics
1 answer:
SashulF [63]3 years ago
8 0

Answer:

21

Step-by-step explanation:

p(x)=1/2(x-2)(x-3)(x+7)

costant term=1/2(-2)(-3)(7)=21

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Give the standard form for 80.000 + 200 + 2.
Masja [62]
80202 that’s the answer
8 0
3 years ago
Help me solve this image please!!!
tresset_1 [31]

Based on the information, Christian would have $5525.5 of an annuity.

<h3>How to calculate the annuity?</h3>

According to the given information, the number of coffees per week is 3 then, per month is 3x4 = 12

Each coffee is $4.5. Then monthly expenditure for coffees is 12 x 4.5 = $54

Rate of interest r = 1.6% = 1.6/100 = 0.016 and for monthly compounding r = 0.016/12 = 0.00133

n = number of payments = 8 x 12 = 96

We can use the formula for finding the future value as below

FV = C x [ ( 1 + r )n-1 ] / ( r )

FV = 54 x [ ( 1 + 0.00133 )96 – 1 ] / (0.00133)

= 54 x [ (1.13609 - 1)] / (0.00133)

= 54 x 0.13609 / (0.00133)

= 54 x 102.3233

= 5525.5

Therefore Christian would have $5525.5 of the annuity.

Learn more about annuity on:

brainly.com/question/5303391

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5 0
2 years ago
PLS HELP ME! I DONT KNOW WHAT TO DO FOR THIS
kotykmax [81]

Answer:

Step-by-step explanation:

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2-4/1-3

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8 0
3 years ago
Read 2 more answers
It would take an hour for plane A to meet plane B which is flying towards it. If the distance between them will be 200 miles aft
sammy [17]
Let a = speed of the plane A, and b = speed of plane B.
(Assume that the net effect of the wind is negligible.)
From the first sentence, the distance between A and B after each travels for 1 hour is a + b miles. From the second sentence, after 45 minutes, or 0.75 hour, the distance between A and B is 200 miles. Plane a has traveled 0.75a, while plane B has traveled 0.75b.
Hence a + b = 0.75a + 0.75b +200
==> 0.25(a + b) = 200.
==> a + b = 800.
Therefore planes A and B are 800 miles apart now.
3 0
3 years ago
Read 2 more answers
Could you help plz.​
I am Lyosha [343]

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

Solution:

Let f be the bags of flour and b be the pounds of butter.

Cost of 20 bags of flour 16 pound of butter = 110

⇒ 20f + 16b = 110 -------------------- (1)

Cost of 30 bags of flour 12 pound of butter = 120

⇒ 30f + 12b = 120  -------------------- (2)

Equation (1) and (2) are the system of equations.

(2) ⇒ 30f + 12b = 120

Subtract 30f from both sides.

⇒ 12b = 120 – 30f

Divide by 12 on both sides.

$\Rightarrow b =\frac{120-30f}{12}  -------------------- (3)

Substitute (3) in (1).

$20f+16\left(\frac{120-30f}{12}\right)=110

$20f+4\left(\frac{120-30f}{3}\right)=110

$20f+4(40-10f)=110

$20f+160-40f=110

Subtract 160 from both sides.

$-20f=-50

Divide by –20, we get

$f=\frac{5}{2}

f = 2.50

Substitute f = 2.5 in equation (3), we get

$\Rightarrow b =\frac{120-30(2.50)}{12}

$b=\frac{15}{4}

b = 3.75

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

7 0
3 years ago
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