Witch Is egghead and witch not egghead

Mathematics

1 answer:

lapo4ka [179]3 years ago

8 0

Answer:

hahah first one egghead, 2nd one not egghead

Step-by-step explanation:

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Find the sum <br>6+9+12+...+93<br><br>Sn=

Burka [1]

We notice that:
9-6 = 3
12-9 = 3 , Then we can conclude that this is an arithmetic progression with:
1st term a₁ = 6 and with common difference d = 3

So the first term is 6 and the last term is 93.
the formula of the sum in a A.P is :

S = (a + last term).n/2, n being the rank of the last term. So to be
able to find S, we have to calculate the value of n

We know that the last value of a A.P is :
last value = a₁ + (n-1)d
93 = 6 +(n-1)(3) → 93 = 6 + 3n -3 → n = 90/3 → n = 30 (rank 30th)

Now we can find the sum:
S = (a₁ + last term)n/2

S = (6+93)30/2

S = (99).15 = 1,485

7 0

3 years ago

Express 34% as a fraction in simplest form?

romanna [79]

Answer is 17/50

Step-by-step explanation: 34/100 = 17/50 easy :D

7 0

3 years ago

Read 2 more answers

you are rolling a 10-sided die with sides numbered 1-10. you keep rolling the die until you roll a prime number and then stop. l

evablogger [386]

The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number

In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number

Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)

Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)

Let X be the number of times the die is rolled

The probability of getting a prime =

$P(Prime) = \frac{4}{10}$

Now, the value of

E(X)=∑x.P(x) [ x-> {1, infinity}]

= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)

= 1. $\frac{4}{10}$ + 2. $\frac{6}{10}$ . $\frac{4}{10}$ + 3. $\frac{6}{10}$ . $\frac{6}{10}$ $\frac{4}{10}$ + 4. $\frac{6}{10}$ . $\frac{6}{10}$ . $\frac{6}{10}$ . $\frac{4}{10}$ .......