8p + 3q - 18 when p = 1/2 and q = 7
You are given that p is equal to 1/2 and q is equal to 7, so plug these values into p and q in the expression to find your answer.
Rewrite your expression to include the values of p and q plugged in. Your expression should look like:
8(1/2) + 3(7) - 18
According to PEMDAS, multiplication should be solved first before doing subtraction, so multiply 8 by 1/2 and 3 by 7. Rewrite your expression; your expression should look like this:
4 + 21 - 18
According to PEMDAS, addition and subtraction should be solved from left to right; they are not prioritized. So solve the expression from left to right and then you will have your answer.
4 + 21 = 25
25 - 18 = 7
Your answer is 7.
Answer:
x = 5.4
Step-by-step explanation:
Multiply 7.2 by 3/4 to find the equivalent ratio.
X=132
To find y
180-132= 48
180-68-48=64
y=64
First, let's calculate the mean and the mean absolute deviation of the first bowler.
FIRST BOWLER: <span>8,5,5,6,8,7,4,7,6
Mean = (Sum of all data)/(Number of data points) = (8+5+5+6+8+7+4+7+6)/9
<em>Mean = 6.222</em>
Mean absolute deviation or MAD = [</span>∑(|Data Point - Mean|]/Number of Data Points
MAD = [|8 - 6.222| + |5 - 6.222| + |5 - 6.222| + |6 - 6.222| + |8 - 6.222| + |7 - 6.222| + |4 - 6.222| + |7 - 6.222| + |6 - 6.222|]/9
<em>MAD = 1.136</em>
SECOND BOWLER: <span>10,6,8,8,5,5,6,8,9
</span>Mean = (Sum of all data)/(Number of data points) = (<span>10+6+8+8+5+5+6+8+9</span>)/9
<em>Mean = 7.222</em>
Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points
MAD = [|10 - 7.222| + |6 - 7.222| + |8 - 7.222| + |8 - 7.222| + |5 - 7.222| + |5 - 7.222| + |6 - 7.222| + |8 - 7.222| + |9 - 7.222|]/9
<em>MAD = 1.531
</em>
The mean absolute deviation represents the average distance of each data to the mean. Thus, the lesser the value of the MAD is, the more consistent is the data to the mean. <em>B</em><em>etween the two, the first bowler is more consistent.</em>
Answer:
-16
Step-by-step explanation:
Given the sequence:
b(n)=b(n−1)−7, where b(1)=−2
b(2)=b(2−1)−7
=b(1)−7
=-2-7
b(2)=-9
Therefore, the 3rd term of the sequence
b(3)=b(3−1)−7
=b(2)-7 (Recall b(2)=-9 from above)
=-9-7
b(3)=-16
The 3rd term of the sequence is -16.
