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3 years ago

Wich equation shows y + 1/5 = 3x in standard form

Mathematics

1 answer:

Katen [24]3 years ago

4 0

15x - 5y = 1 it's B in standard form

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What is 4/6 equal to

timama [110]

$\frac{2}{3}$

8 0

3 years ago

Find the product and simplify your answer. 7a5(-3a4+5a-5)

Alex Ar [27]

$\text{Hey there!}$

$\mathsf{Use\ distributive\ property\ to\ solve}}\\\\\text{The formula is : a(b + c)=a(b)+a(c)=b+ac}\\\\\mathsf{7a^5(-3a^4+5a-5)}\\\\\mathsf{7a^5(-3a^4)=-21a^9}\\\\\mathsf{7a^5(5a)=3a^6}\\\\\mathsf{7a^5(-5)=-35a^5}$

$\boxed{\boxed{\mathsf{Your\ answer: \boxed{\mathsf{-21a^9+35a^6-35a^5}}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

3 0

3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

4 years ago

Read 2 more answers

Can someone please explain to me how to find the value of m? thanks<br>-10 = -10 + 7m

GarryVolchara [31]

      -10 = -10 + 7m

Add 10 to each side: 0 = 7m

Divide each side by 7 : 0 = m

Please take a second and just LOOK at the equation you started with.
It says:

-- You have this number '-10' .

-- Your number -10 is going to be exactly the same size
   after you add 7 of something to it.

The ONLY way that could happen is if the 'something' is 'nothing' .

   ' m ' must be nothing.

8 0

4 years ago

Read 2 more answers

The population of Groverdale is

wolverine [178]

Answer: Yes alaina is correct

Step-by-step explanation: first look at the populations

553,000

535,841

Tittlehook has a 3 in the ten thousands place whilst groverdale has a 5 in the thousands place.

Hope this helps :)

6 0

3 years ago