Answer:
if ur trying finding the y-intercept it's -24
Step-by-step explanation:
slope- intercept form is y=mx+b we know m is 4 (7,4) 7 is the x 4 is the y ...
then you plug them in and we know 4 times 7 is 28 and then 4-s8 is -24
First, we convert the interest such that it is compounded annually. The formula would be:
ieff = (1 + i/m)^m - 1
where m = 4, since there are 4 quarters in a year
ieff = (1 + 0.025/4)^4 - 1
ieff = 0.0252
Then we use this for this equation:
F = P(1 + i)^n, where F is the future worth, P is the present worth and n is the number of years
F = $600(1 + 0.0252)^15
F = $871.53
The answer is 19.7 hope it helps!!! :)
Answer:
12
Step-by-step explanation:
let's say number of patches is x, and amount of time is y. the time per patch is k.
k * x = y
2 * k = 4
k = 2
2 * x = y
2 * 6 = 12
The functions f(4x-3)≥f(2-x^2) and f(5-x^2)≥f(3x-5) are quadratic functions
The values of the inequalities are -5 ≤ x ≤ 1 and -5 ≤ x ≤ 2
<h3>How to solve the inequalities?</h3>
<u>Inequality 1: f(4x - 3) ≥ f(2 - x^2), Df = (-8 , 4)</u>
The function increases at (-8,4).
So, we have:
4x - 3 ≥ 2 - x^2
Rewrite as:
x^2 + 4x - 2 - 3 ≥ 0
Evaluate the like terms
x^2 + 4x - 5 ≥ 0
Expand
x^2 + 5x - x - 5 ≥ 0
Factorize the expression
x(x + 5) - 1(x + 5) ≥ 0
Factor out x + 5
(x - 1)(x + 5) ≥ 0
Solve for x
x ≥ 1 or x ≥ -5
Rewrite as:
-5 ≤ x ≤ 1
<u>Inequality 2: f(5 - x^2) ≥ f(3x - 5), Df=(-∞,4)</u>
The function decreases at (-∞,4).
So, we have:
5 - x^2 ≥ 3x - 5
Rewrite as:
x^2 + 3x - 5 - 5 ≤ 0
Evaluate the like terms
x^2 + 3x - 10 ≤ 0
Expand
x^2 + 5x - 2x - 10 ≤ 0
Factorize the expression
x(x + 5) - 2(x + 5) ≤ 0
Factor out x + 5
(x - 2)(x + 5) ≤ 0
Solve for x
x ≤ 2 or x ≤ -5
Rewrite as:
-5 ≤ x ≤ 2
Hence, the values of the inequalities are -5 ≤ x ≤ 1 and -5 ≤ x ≤ 2
Read more about inequalities at:
brainly.com/question/11234618