Answer:
350 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) of Go Kart = 35 kg
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Force (F) =?
Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Final velocity (v) = 0 m/s
Acceleration (a) =.?
v² = u² + 2as
0² = 12² + (2 × a × 7.2)
0 = 144 + 14.4a
Collect like terms
0 – 144 = 14.4a
– 144 = 14.4a
Divide both side by 14.4
a = – 144 / 14.4
a = – 10 m/s²
The negative sign indicate that the Go Kart is decelerating when the brake was applied.
Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:
Mass (m) of Go Kart = 35 kg
Acceleration (a) = 10 m/s
Force (F) =?
F = ma
F = 35 × 10
F = 350 N
Thus, the Go Kart has a force of 350 N when the student locked the brake.
Light is refracted when it crosses the interface from air into glass in which it moves more slowly. Since the light speed changes at the interface, the wavelength of the light must change, also. The wavelength decreases as the light enters the medium and the light wave changes direction.
Answer:
See explanation below
Explanation:
In this case, let's draw the triangle so we can see how the resultant force would be.
In the picture below, you have the drawn, and the procedure to solve this.
Hope this helps
Answer:
Explanation:
Given that,
Height of the inclined plane, h = 2.02 m
Final velocity of the object, v = 5.72 m/s
To find,
The moment of inertia of the object.
Solution,
As the object rolls down the inclined plane, its gravitational potential energy gets converted to the kinetic energy along with rotational kinetic energy.
Since,
On rearranging the above equation and finding the value of I as :
So, the moment of inertia of an object that rolls without slipping down is
I hope I can help! :)
A concave mirror is when the object is anywhere from infinity to focus the image so form will be real and inverted.
And when the object is between pole and focus of concave mirror then image so formed will be virtual and erect and the size of image is greater than size of object.
So, the answer would be "where light rays disperse."
Have a great day/evening/night! :)
Let me know if you have any additional questions!
-Kappifilms