What is the name of the device that senses the current flowing, tripping the circuit, and cutting off the electricity?

1 answer:

7 0

Answer: A fuse

Explanation:
A fuse is a thin piece of wire that heats and melts when the electric current in a circuit exceeds a safe value, thereby tripping the circuit and cutting off the electric current flow.

You might be interested in

A thermometer is placed in water in order to measure the water's temperature period what would cause the liquid in the thermomet

Naddik [55]

The thermal energy of the water. Because the water is waaay above Absolute Zero (0K, or -273,15 C) it holds thermal energy or aka the temperature of the water. If the temperature of the water is higher than the one in the thermometer, the heat will 'flow' into the liquid (mostly mercury or modern, it is ethanol), causing the liquid to rise since it's volume increases. The same when te water has lower temperature. The thermal energy of the thermometer will 'flow' in the water and the volume shrinks, causing the liquid to go down. Simple thermodynamics.

7 0

4 years ago

I have a taut string and I flick one end to make a wave travel through it. If I increase the tension in the string by 20% and fl

Harrizon [31]

Answer: The speed of the wave propagation and the frequency of the fundamental harmonic would increase by 9.5%.

Explanation: The speed of wave propagation through a string is given by

$v=\sqrt{\frac{T}{\rho}}$

where $\rho[/\tex] is the linear density of the material the string is made of and [tex]T$ is the tension. The fundamental harmonic of the string is the one that has its wavelength equal to $2L$ , where $L$ is the length of the string so we have for its frequency

$f=\frac{v}{\lambda}=\frac{v}{2L}=\frac{1}{2L}\sqrt{\frac{T}{\rho}}.$

Now if the tension increases by 20% we would have $T'=1.2T$ and also

$v'=\sqrt{\frac{T'}{\rho}}=\sqrt{\frac{1.2T}{\rho}}=\sqrt{1.2}\sqrt{\frac{T}{\rho}}=1.095v$

and, similarly

$f'=\frac{1}{2L}\sqrt{\frac{T'}{\rho}}=1.095f.$

This means that the speed of the wave propagation and the frequency of the fundamental harmonic would increase by 9.5%.

6 0

4 years ago

Please help and explain please thank youu

vekshin1

Answer:

Series circuits = D & E

parallel circuits = C & F

Circuit C is connected in parallel and circuit D is connected in series.

Circuit D and E are the same, despite the switch is located in a different position, they are working in series.

Circuits C and F are the same, they are connected in parallel.

There will be only one bulb in on mode and it is in the circuit F.

Explanation:

In the attached image, we can see a serial circuit and a parallel circuit. Serial circuits are characterized by sharing the same current, if the current step is interrupted (opening the switch), the current will not flow and no element (light bulbs off) will work. When a circuit is connected in parallel, they share the same voltage within the circuit. All resistive elements or bulbs are located between nodes 1 and 2, so they share the same voltage.

The special case are the circuits C and F, both are connected in parallel. But in circuit C the switch is near to the voltage source, therefore when the switch is unplugged there won't be the main current and the bulbs will be off.

In-circuit F, when the switch is off only the bulb near to the switch won't work the other bulb will be working because the main current is passing through it.