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4 years ago

8

How would seasons on earth be different if the earth was not tilted on its axis

1 answer:

MakcuM [25]4 years ago

5 0

If the Earth's axis were 'straight' ... pefectly perpendicular to the ecliptic
plane ... then:

-- Day and night would be the same length ... every day of the year,
everywhere on Earth !

-- There wouldn't be any seasons, anywhere. There might still be some
'weather' ... cloudy days, sunny days, occasional rain, wind etc. But
there would be no average change during the year. No hot months or
cold months. In any one place, the weather would always be generally
the same, every day, all year. Everywhere all around the equator would be
generally the hottest on Earth, and the local climates would generally get
cooler as you moved away from the equator and toward the poles.

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New 5G networks utilize millimeter-wave radiation. Millimeter-wave radiation refers to electromagnetic waves with frequencies in

seraphim [82]

Answer:

It corresponds to 1mm-10 mm range.

Explanation:

Electromagnetic waves (such as the millimeter-wave radiation) travel at the speed of light, which is 3*10⁸ m/s in free space.
As in any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

$v = \lambda * f (1)$

Replacing v= c=3*10⁸ m/s, and the extreme values of f (which are givens), in (1) and solving for λ, we can get the free-space wavelengths that correspond to the 30-300 GHz range, as follows:

$\lambda_{low} = \frac{c}{f_{high}} = \frac{3e8m/s}{300e9Hz} = 1 mm (2)$

$\lambda_{high} = \frac{c}{f_{low}} = \frac{3e8m/s}{30e9Hz} = 10 mm (3)$

4 0

3 years ago

WILL MARK BRAINLIEST <br> How do you convert Farenheit to Celcius<br> and Celcius to Farenheit

olya-2409 [2.1K]

Answer:

F= $\frac{9}{5}C+32$

C= $\frac{5}{9}(F-32)$

F stands for farenheit

C stands for celcius

Explanation:

3 0

4 years ago

Read 2 more answers

As you approach a bicyclist traveling in your lane, adjust your speed and position and do not pass if the road is too _______ fo

tatiyna

Answer:

correct answer is narrow

Explanation:

solution

when we pass someone riding bicycle ahead you then we should decrease our speed and increase the distance between you and bicyclist

and we should ride on road with very predictable manner and we should ride in straight line and if If road is too narrow for a bicycle

then we should ride vehicle to travel side by side so bicyclist should occupy lane until it safe

so here correct option is narrow

5 0

3 years ago

When an earthquake occurs, two types of sound waves are generated and travel through the earth. The primary, or P, wave has a sp

Zielflug [23.3K]

Answer: $d=7.94\times 10^5\ m$

Explanation:

Given

Speed of Primary wave $v_1=8\ km/s$

Speed of secondary wave $v_2=4.5\ km/s$

difference in timing of two waves are $77.2\ s$

Suppose both travel a distance of d km then

$t_1=\frac{d}{8}\quad \ldots (i)$

$t_2=\frac{d}{4.5}\quad \ldots (ii)$

Subtract (ii) from (i)

$\frac{d}{4.5}-\frac{d}{8}=77.2$

$d[\frac{1}{4.5}-\frac{1}{8}]=77.2$

$d[0.0972]=77.2$

$d=794.23\ km$

$d=7.94\times 10^5\ m$

7 0

3 years ago

Suppose a certain battery has an internal emf of 9.00 V but the potential difference across its terminals is only 80.0 % of that

Rudiy27

Answer:

$1140.48\times 10^{-6}J$

Explanation:

We have given that the battery has an internal emf of 9 volt

So E = 9 volt

Capacitance $C=44\mu F=44\times 10^{-6}F$

It is given that on the terminal voltage is only 80% of potential difference

So V = 0.8×9 = 7.2 volt

We know that energy stored in the capacitor is given by

$E=\frac{1}{2}CV^2=\frac{1}{2}\times 44\times 10^{-6}\times 7.2^2=1140.48\times 10^{-6}J$

8 0

3 years ago