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Whitepunk [10]
4 years ago
10

A European species of marsh grass called Spartina maritima has a diploid number (2n) of 60. A similar species native to North Am

erica, S. alterniflora, has 2n = 62. In 1835, the North American species was found growing near the European species in Southampton, England, after being accidentally imported. Occasional sterile hybrids were noted. In 1895 a new species, S. anglica, was first identified at Southampton and subsequently became common. The new species has been identified as a fertile hybrid of the original two species. What is the 2n chromosome number of the hybrids that formed from the original two species S. maritima and S. alterniflora?
Biology
1 answer:
puteri [66]4 years ago
7 0

Answer:

2 n = 61 Chromosomes

Explanation:

If the plants that are produced are fertile then they must have a chromosome number hybrid of previous two species and that is 122. This is an example of tetraploidy. It is crucial that the chromosome number of the species should be even otherwise the pairing will result in a mismatch and the produced offspring will be a sterile hybrid.

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What is the formula for the compound formed when aluminum ions (Ap) and chloride bons (CH) Unite?
Tom [10]

Answer:

D.) AICI3

Explanation:

An ionic compound has be neutral, meaning the positive and negative charges have to be equal. So we need three chloride ions to bond with one aluminum ion, and the formula for aluminum chloride is AlCl3

5 0
3 years ago
14). During the early 1700’s, a small group of pacifist Protestants fled Germany to avoid religious persecution. This group, the
abruzzese [7]
A) In the Dunker population, the frequency of IB allele is 0.3 and the frequency of i allele is 0.4. In the general population, the frequency of IB allele is 0.1 and t<span>he frequency of i allele is 0.5.
</span>
If:
I^{A} - <span>the frequency of IA allele
</span>I^{B} - <span>the frequency of IB allele
</span>i - t<span>he frequency of i allele

Then:
</span>I^{A} I^{A} + <span>I^{A} i - the frequency of individuals with A blood type
</span>I^{B} I^{B} + <span>I^{B} i - the frequency of individuals with B blood type
</span>ii <span>- the frequency of individuals with O blood type
</span>
Let's first take a look on the Dunker population:
I^{A} = 0.3
ii=0.16&#10;

<span>Since there is only one possible genotype for O individuals - ii - the frequency of the allele i is square root of the frequency of O individuals:
</span>i= \sqrt{ii}
⇒ i =  \sqrt{0.16}
⇒ i=0.4

Now, we have the frequencies of two alleles (I^{A} and i). To calculate the frequency of I^{B}<span> allele, we will use the formula:
</span>I^{A} + I^{B} + i = 1
⇒ I^{B} = 1- I^{A} - i
⇒ I^{B} = 1-0.3-0.4
⇒ I^{B} = 0.3

Now, in the general population:
I^{A} = 0.4
ii=0.25

<span>Similarly to the work for the Dunker population:
</span>i= \sqrt{ii}
⇒ i = \sqrt{0.25}
⇒ i=0.5

I^{A} + I^{B} + i = 1
⇒ I^{B} = 1- I^{A} - i
⇒ I^{B} = 1-0.4-0.5
<span>⇒ I^{B} = 0.1
</span>


b) A founder effect is a result of geographical separation of a few individuals from the original population. Those founding individuals will form a new population. The Dunker population was not only geographically separated, but also genetically. The group interbreeding was present resulting in increasing those allele frequencies that were the most common in the founding population. In this case, the most individuals from the founding population had B blood type.
6 0
4 years ago
The farmer’s daughter wants a white horse. All of the farmer’s current horses are brown. With what breed of horse should the far
Illusion [34]

Answer: Two of the children of the brown bc they have a higher chance of having a white horse. Or they can just buy one

Explanation:

7 0
3 years ago
Short hair (L) is dominant over long hair (1) in rabbits. Two heterozygous rabbits are mated. Show the punnett square. What phen
Gekata [30.6K]

Answer:

When two heterozygous short haired rabbits are crossed, the short hair being dominant and the long hair recessive, the phenotypes in the offspring will be 75% short hair and 25% long hair, with a short hair:long hair ratio of 3:1.

Explanation:

The crossing of two hybrid individuals for a trait has the probability of producing <u>offspring that exhibit the dominant trait at 75% and the recessive trait at 25%, with the ratio of the dominant trait to the recessive trait being 3:1</u>.

Considering the hair length trait, in rabbits the short hair (L) is the dominant trait and the long hair (L) is recessive, two heterozygous hybrid individuals Ll are crossed:

<em><u>Genotype of the parents</u></em>:

  • ♂ Ll
  • ♀ Ll

Ll X Ll

<u>Punnett Square </u>

Alleles        L      l

L                 LL    Ll

l                  Ll      ll

Where the offspring have a genotype:

<em>Ll 50% </em>

<em>LL 25% </em>

<em>ll 25% </em>

With a ratio Ll:LL:ll of 3:1:1.

Phenotype:

<em>Short hair 75%. </em>

<em>Long hair 25%. </em>

Phenotypic ratio short hair: 3:1 long hair.

In the crossing of two heterozygous short-haired rabbits, taking into account the dominance of the short hair,  phenotypes in the offspring will be 75% short hair and 25% long hair, with a short hair:long hair ratio of 3:1

8 0
3 years ago
Por donde se transportan las celulas defensivas
Alja [10]

Answer: Los distintos órganos linfoides están interconectados por vasos sanguíneos y vasos linfáticos, de modo que se constituye un sistema unitario, entrelazado y bien comunicado. Estos vasos transportan células del sistema inmune, de las cuales el tipo central es el linfocito.

Explanation:

Brainly

6 0
3 years ago
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