This is how the sketch should look on your graph!
= -30a^5b + 12a^4b^3 + 6a^3b^2 + 10a^3b^2 - 4a^2b^4 - 2ab^3
= -30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2ab^3
answer
B. -30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2ab^3
Answer:
center = 98.6, variability = 0.08
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , the sample means with size n of at least 30 can be approximated to a normal distribution with mean and standard deviation
The center is the mean.
So
The standard deviation of the sample of 50 adults is the variability, so
So the correct answer is:
center = 98.6, variability = 0.08
The distance between P and Q is 10 units. hope this helps have a nice day