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3 years ago

1/4 kilometer in 1/3 hour?

Mathematics

1 answer:

german3 years ago

3 0

Answer:

That means it will take you 1 and 1/3 hour to go a kilometer.

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What is 1.701×10−61.701×10−6 written in standard form?

Paraphin [41]

That would be <span>0.00000171</span>, if I'm not mistaken

6 0

4 years ago

Someone help me with this please, I really need help, and it's due tmrw...PLEASE

UNO [17]

Answer:

y=(x*9)-4

Step-by-step explanation:

for example:

0*9=0

0-4=-4

4*9=36

36-4=32

2*9=18

18-4=14

hope this helped ;)

6 0

3 years ago

Read 2 more answers

I need help<br>I hate math guys

lbvjy [14]

Answer:

4 * 2y + 4 * 1

4(2y + 1)

Distributive property

Step-by-step explanation:

8y + 4

We can factor out a 4 out of both as both are divisible by 4

8y / 4 = 2y

4 / 4 = 1

So 8y + 4 is the same as saying 4 * 2y + 4 * 1

This can be written as 4(2y + 1) which is written using the distributive property

8 0

3 years ago

PLEASE HELP!! DUE REALLY SOON (LINK)

andre [41]

Answer:

youngest=115

middle=150

elder=230

Step-by-step explanation:

let the youngest be x

the middle will be x+35

the oldest will be 2x

x+x+35+2x=495

4x+35=495

4x=495-35

4x=460

x=115

since the youngest is x,the money he will receive is $115.

the middle will be x+35 which is equal to 115+35=$150.

lastly the oldest will be 2x which is equal to 2×115=$230.

7 0

3 years ago

Read 2 more answers

Find the point P on the line yequals=33x that is closest to the point (60 comma 0 )(60,0). What is the least distance between P

scoray [572]

Answer:

$18\sqrt{10}$ units$

Step-by-step explanation:

We are given the equation of the line y=3x and a point, say Q(60,0) outside of that line.

We want to find the point on the line y=3x which is closest to Q.

Let P(x,y) be the desired point. Since it is on the line y=3x, it must satisfy the line.

If x=a, y=3a, so the point P has the coordinates (a,3a).

Distance between point Q and P

$=\sqrt{(60-a)^2+(0-3a)^2}\\D =\sqrt{10a^2-120a+3600}$

To minimize D, we find its derivative

$\dfrac{dD}{da}=\dfrac{10a-60}{\sqrt{10a^2-120a+3600} }\\$Setting \dfrac{dD}{da}=0\\10a-60=0\\10a=60\\a=6$

Therefore, the y-coordinate for P is 3*6=18.

The point P=(6,18).

Next, we calculate the distance between P(6,18) and (60,0).

$D =\sqrt{10(6)^2-120(6)+3600}\\=\sqrt{3240}\\=18\sqrt{10}$ units$

8 0

4 years ago