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lara [203]
3 years ago
6

How do you simplify this ? 8(x - 4) - 6(x - 1) + 9x

Mathematics
2 answers:
True [87]3 years ago
8 0
8(x - 4) - 6(x - 1) + 9x=\\
8x-32-6x+6+9x=\\
11x-26
Neporo4naja [7]3 years ago
4 0
8(x-4)-6(x-1)+9x\\\\=8\cdot x+8\cdot(-4)-6\cdot x-6\cdot(-1)+9x\\\\=8x-32-6x+6+9x\\\\=(8x-6x+9x)+(-32+6)\\\\=\boxed{11x-26}
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5. A fruit concentrate is sold in 250 mL packs. The instructions are 'Add water to make one litre of ready-to-drink fruit juice'
Ierofanga [76]
Given ,

Concentrate= 250 mL

Water = 1 liter = 1000 mL

A) ratio is 250:1000 = 1:4

B) for 250 mL it is 1 liter now for 2000mL it is X .

=> x = 2000/250 = 8 liters

C) volume of water in 6L of made up juice is 1500 mL

D) 1 liter - 5 glasses

For 80 glasses it would be 80/5 = 16 glasses
4 0
2 years ago
Paul's family drove 377 mi to the beach averaging 58 ​ mi/h ​ on the way there. On the return trip home, they averaged 65 ​ mi/h
sashaice [31]
The answer is 12.3 hours
6 0
3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
Solving Inequalities Using Addition or Sub
wariber [46]
I believe it’s x < 9
7 0
3 years ago
PLEASE HELP ASAP!!
Nitella [24]

Answer:

The radius of a sphere is 2 millimeters

The surface area of a sphere is 50.24 square millimeters.

The circumference of the great circle of a sphere is 12.56  millimeters.

Step-by-step explanation:

<u><em>Verify each statement</em></u>

case A) The radius of a sphere is 8 millimeters

The statement is false

we know that

The volume of the sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

V=100.48/3\ mm^{3}

\pi =3.14

substitute and solve for r

100.48/3=\frac{4}{3}(3.14)r^{3}

r^{3}=(100.48)/(4*3.14)

r=2\ mm    

case B) The radius of a sphere is 2 millimeters

The statement is True

(see the case A)

case C) The circumference of the great circle of a sphere is 9.42 square millimeters  

The statement is false

The units of the circumference is millimeters not square millimeters

The circumference is equal to

C=2\pi r

we have

r=2\ mm  

\pi =3.14

substitute

C=2(3.14)(2)

C=12.56\ mm

case D) The surface area of a sphere is 50.24 square millimeters.

The statement is True

Because

The surface area of the sphere is equal to

SA=4\pi r^{2}

we have

r=2\ mm  

\pi =3.14

substitute

SA=4(3.14)(2)^{2}

SA=50.24\ mm^{2}

case E)  The circumference of the great circle of a sphere is 12.56  millimeters.  

The statement is true

see the case C

case F) The surface area of a sphere is 25.12 square millimeters

The statement is false

because the surface area of the sphere is SA=50.24\ mm^{2}

see the case D

7 0
3 years ago
Read 2 more answers
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